CODEWITHSUNDEEP
javascriptjqueryhtmlarrays
guradio
guradio

Reputation: 15555

combining data/variables jquery

var student = [{
    "fname": "Jackie",
    "mname": "Lee",
    "lname": "Li"
}, {
    "fname": "Ken",
    "mname": "Ryu",
    "lname": "Sha"
}];

for (var i = 0; i < student.length; i++) {
    console.log(student[i].fname + " " + student[i].mname + ". " + student[i].lname ? student[i].fname + " " + student[i].mname + ". " + student[i].lname + " , " : " ");
}

I am trying to combine names in the a td these names are from an array. I was able to make the names combine by above code. problem is on the last name there is still a , just want to get rid of the comma when there are no more names that will follow. I am bugged by this simple comma for hours. any idea is appreaciate.

FIDDLE

Upvotes: 1

Views: 84

Answers (4)

Sebastian Hens
Sebastian Hens

Reputation: 157

If I understand your question right than this should do it:

for(var i = 0 ; i < student.length; i++){
  var name = student[i].fname + " " + student[i].mname + ". " + student[i].lname ?  student[i].fname + " " + student[i].mname + ". " + student[i].lname: " ";
  if (i < (student.length - 1)) {
      name += ',';
  }
}

Upvotes: 3

Tharindu Kumara
Tharindu Kumara

Reputation: 4458

Try this bit of code

var student = [{
  "fname": "Jackie",
  "mname": "Lee",
  "lname": "Li"
}, {
  "fname": "Ken",
  "mname": "Ryu",
  "lname": "Sha"
}]

for (var i = 0; i < student.length; i++) {
  var out = student[i].fname + " " + student[i].mname + ". " + student[i].lname;
  if (i < student.length - 1) {
    out += ", ";
  } else {
    out += " ";
  }
  snippet.log(out);
}
<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

Upvotes: 3

T.J. Crowder
T.J. Crowder

Reputation: 1074266

One easy way is to build up an array and then using .join(", "):

var student = [{
  "fname": "Jackie",
  "mname": "Lee",
  "lname": "Li"
}, {
  "fname": "Ken",
  "mname": "Ryu",
  "lname": "Sha"
}];

var names = [];
for (var i = 0; i < student.length; i++) {
  names.push(student[i].fname + " " + student[i].mname + ". " + student[i].lname);
}
snippet.log(names.join(", "));
<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

It can even be more concise with Array#map:

var student = [{
  "fname": "Jackie",
  "mname": "Lee",
  "lname": "Li"
}, {
  "fname": "Ken",
  "mname": "Ryu",
  "lname": "Sha"
}];

snippet.log(student.map(function(entry) {
  return entry.fname + " " + entry.mname + ". " + entry.lname;
}).join(", "));
<!-- Script provides the `snippet` object, see http://meta.stackexchange.com/a/242144/134069 -->
<script src="http://tjcrowder.github.io/simple-snippets-console/snippet.js"></script>

Upvotes: 6

Alex Filatov
Alex Filatov

Reputation: 2321

Try this jsfiddle

you should use like this:

var student = [{
     "fname": "Jackie",
         "mname": "Lee",
         "lname": "Li"
 }, {
     "fname": "Ken",
         "mname": "Ryu",
         "lname": "Sha"
 }]

 for (var i = 0; i < student.length; i++) {
     console.log(student[i].fname + " " + student[i].mname + ". " + student[i].lname + ((i < student.length - 1) ? ", " : " "));
 }

Upvotes: 2

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