paidedly
paidedly

Reputation: 1413

Why final Byte as a case in switch statement doesn't compile?

byte a = 125;
final byte b = 2;
final Byte c = 3;
switch (a) {
case b: // works fine
    break;
case c: // Constant Expression required
    break;
}

Since cis a final variable, isn't it a compile time constant and hence a valid case label?

Upvotes: 3

Views: 228

Answers (1)

Jon Skeet
Jon Skeet

Reputation: 1502825

Since c is a final variable, isn't it a compile time constant

No. The rules for constant expressions are given in JLS 15.28, and they don't include wrapper types:

A constant expression is an expression denoting a value of primitive type or a String that does not complete abruptly and is composed using only the following [...]

A wrapper type is neither a primitive type nor String.

Upvotes: 5

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