Reputation: 938
Say for example you have something like this, trying to make the example as simple as possible.
type Home struct {
Bedroom string
Bathroom string
}
How do you pass the field name, or can you, to a function?
func (this *Home) AddRoomName(fieldname, value string) {
this.fieldname = value
}
Obviously that does not work... The only way I can see to do this is to use two functions which adds a lot of extra code when the struct gets really big and has a lot of similar code.
func (this *Home) AddBedroomName(value string) {
this.Bedroom = value
}
func (this *Home) AddBathroomName(value string) {
this.Bathroom = value
}
Upvotes: 0
Views: 974
Reputation: 101
Use type assertions on an interface value:
package main
import "fmt"
type Test struct {
S string
I int
}
func (t *Test) setField(name string, value interface{}) {
switch name {
case "S":
t.S = value.(string)
case "I":
t.I = value.(int)
}
}
func main() {
t := &Test{"Hello", 0}
fmt.Println(t.S, t.I)
t.setField("S", "Goodbye")
t.setField("I", 1)
fmt.Println(t.S, t.I)
}
Upvotes: 0
Reputation: 23881
One more idea that comes to my mind is like this, not sure if it makes sense in your case though:
func Set(field *string, value string) {
*field = value
}
home := &Home{"asd", "zxc"}
fmt.Println(home)
Set(&home.Bedroom, "bedroom")
Set(&home.Bathroom, "bathroom")
fmt.Println(home)
http://play.golang.org/p/VGb69OLX-X
Upvotes: 0
Reputation: 64677
The only way that I am aware of is to use reflection:
func (this *Home) AddRoomName(fieldname, value string) {
h := reflect.ValueOf(this).Elem()
h.FieldByName(fieldname).Set(reflect.ValueOf(value))
return
}
http://play.golang.org/p/ZvtF_05CE_
Upvotes: 1