CODEWITHSUNDEEP
phparraysfunction
user1274113
user1274113

Reputation: 446

Array search always returns false even if it's not

Ok it's late night and I'm working non-stop from too many hours so here's why I don't manage to understand what's the problem here. I have an array:

Array
(
    [bob] => 
    [mike-2] => 
    [tara] => example.com
)

I want to get the key searching for value so I'm using array_search:

// With an if statement...
if(in_array($_SERVER['SERVER_NAME'], $array)!==false)
{
    // something
}

// ... and also directly with this
$key = array_search($_SERVER['SERVER_NAME'], $array);
echo $key;

Result? Always false! There's no way for me to get tara when I'm looking for example.com. What the heck am I missing? I even tried replacing $_SERVER['SERVER_NAME'] directly with "example.com" but of course it still doesn't work.

Edit: it was a typo error... damn. I wasted 2 hours for this.

Upvotes: 0

Views: 411

Answers (3)

vcanales
vcanales

Reputation: 1828

Stop working. This is an actual answer. Just stop. Whenever it comes to you wasting two hours on a typo you're doing nobody any good, especially yourself.

Rest, you're not getting anywhere like this.

Upvotes: 5

Ankit Arjaria
Ankit Arjaria

Reputation: 111

Array search is case sensitive, $_SERVER['SERVER_NAME'] will return the name in upper case so you have to convert it lower case in your case to work properly, additionally try to map the array also to lowercase Try the given example

$data = array

(
    'bob' =>'', 
    'mike-2' =>'', 
    'tara' =>'example.com'
);
array_search(strtolower($_SERVER['SERVER_NAME']), array_map('strtolower', $data));

Upvotes: 0

Dinuka Dayarathna
Dinuka Dayarathna

Reputation: 169

Try this instead

    $test= array('bob' => '','mike' => '','tara' => 'serverName');
while(list($key,$value) = each($test))
{
    if($value==$_SERVER['SERVER_NAME'])
    {
        echo $key;
        break;
    }
}

Upvotes: 0

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