CODEWITHSUNDEEP
javaregex
Tumeco
Tumeco

Reputation: 115

Regex Match text between 2 Character

I have this kind of line : 

#RT_POOL_CELL1_1 : RT_CELL_T :=  (NEXT     => 0,

#RT_IS_OK                   : BOOLEAN := TRUE;
#RT_RESULT_UPDATE_TM_INFO.TC_INFO : PUS.TYPES.RESULT_UPDATE_TM_INFO_T := PUS.TYPES.UPDATE_OK;

And I need to take RT_POOL_CELL1_1, RT_IS_OK and RT_RESULT_UPDATE_TM_INFO (without the dot .TC_INFO) in java with regex.

I tried to make that with this regex : \s*[#][[:ascii:]]\s*[:|.]

But it doen't work. The thing to know is the word I need to take is always between # and :, they can contains space between word et sign. And if there is a ., I juste take the word before the dot.

Thank's for your help.

Upvotes: 1

Views: 55

Answers (2)

Bohemian
Bohemian

Reputation: 424953

To match the word:

(?<=#)[^: .]+(?=.*:)

See live demo.

Upvotes: 1

anubhava
anubhava

Reputation: 784878

You can use this regex based on lookarounds:

(?<=#)[^:.]+?(?= *[:.])

Breakup of regex:

(?<=#)     # makes sure there is preceding #
[^:.]+?    # match anything but : or . (non-greedy)
(?= *[:.]) # makes sure this is followed by 0 or more spaces and : or .

RegEx Demo

Upvotes: 2

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