CODEWITHSUNDEEP
python
PythonNewBee
PythonNewBee

Reputation: 143

Referencing List Positions of Words

I have a list of words which I have created through an Input statement: phrase = input(Please enter a phrase:) My Name Is My Name Is

phrase.split()
Phrase = ["My", "Name", "Is", "My", "Name", "Is"]

I have then created a UsedWords list (see below) by enumerating through the Phrase list and appending all the Words that were used to create the original phrase.

WordsUsed =  ["My","Name","Is"]
indexOfWords=[0      1     2 ]

I then stored the index of each letter (within the WordsUsed list) into a new list called indexOfWords by using the built-in in method.

So, what I want to do now is re-create the original phrase within the phrase list, but replace it by the index of the Word in the WordsUsed list. So for example:

Phrase = ["My", "Name", "Is", "My", "Name", "Is"]
WordsUsed =  ["My","Name","Is"]
NewPhrase = [0, 1, 2, 0, 1, 2]

I have tried as suggested by Kasra the following:

d={j:i for i,j in enumerate(set(Phrase))}
[d[i] for i in Phrase]

However this returns the following output for the phrase: Phrase = ["My", "Name", "Is", "My", "Name", "Is"] output [2, 1, 0, 2, 1, 0] I belive that it is outputting the list lexicographicaly. The Actual output should be [0, 1, 2, 0, 1, 2]

Does anybody have any ideas on how to overcome this.

Cheers

Upvotes: 3

Views: 83

Answers (1)

thodic
thodic

Reputation: 2259

Try:

[WordsUsed.index(word) for word in Phrase]

What it gives you

Given ["My", "Name", "Is", "My", "Name", "Is"] you'll get [0, 1, 2, 0, 1, 2].

Given ["My", "Name", "My", "My", "Name"] you'll get [0, 1, 0, 0, 1].

Hopefully this is more readable and compact answer.

Upvotes: 3

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