Reputation: 126062
I want to read a file and get back a vector of String
s. The following function works, but is there a more concise or idiomatic way?
use std::fs::File;
use std::io::Read;
fn lines_from_file(filename: &str) -> Vec<String> {
let mut file = match File::open(filename) {
Ok(file) => file,
Err(_) => panic!("no such file"),
};
let mut file_contents = String::new();
file.read_to_string(&mut file_contents)
.ok()
.expect("failed to read!");
let lines: Vec<String> = file_contents.split("\n")
.map(|s: &str| s.to_string())
.collect();
lines
}
Some things that seem suboptimal to me:
String
, which will be thrown away. This would be particularly wasteful if I only wanted the first N lines.&str
per line, which will be thrown away, instead of somehow going straight from the file to a String
per line.How can this be improved?
Upvotes: 50
Views: 37549
Reputation: 431589
DK.'s answer is quite right and has great explanation. However, you stated:
Read a file and get an array of strings
Rust arrays have a fixed length, known at compile time, so I assume you really mean "vector". I would write it like this:
use std::{
fs::File,
io::{prelude::*, BufReader},
path::Path,
};
fn lines_from_file(filename: impl AsRef<Path>) -> Vec<String> {
let file = File::open(filename).expect("no such file");
let buf = BufReader::new(file);
buf.lines()
.map(|l| l.expect("Could not parse line"))
.collect()
}
// ---
fn main() {
let lines = lines_from_file("/etc/hosts");
for line in lines {
println!("{:?}", line);
}
}
AsRef
for the filename.Result::expect
shortens the panic on Err
.BufRead::lines
handles multiple types of newlines, not just "\n"
.BufRead::lines
also gives you separately allocated String
s, instead of one big glob.Vec<String>
).If you wanted to return a Result
on failure, you can squash the implementation down to one line if you want:
use std::{
fs::File,
io::{self, BufRead, BufReader},
path::Path,
};
fn lines_from_file(filename: impl AsRef<Path>) -> io::Result<Vec<String>> {
BufReader::new(File::open(filename)?).lines().collect()
}
// ---
fn main() {
let lines = lines_from_file("/etc/hosts").expect("Could not load lines");
for line in lines {
println!("{:?}", line);
}
}
Upvotes: 40
Reputation: 59095
As BurntSushi said, you could just use the lines()
iterator. But, to address your question as-is:
You should probably read Error Handling in Rust; those unwrap()
s should be turned into ?
s, with the function's result becoming a Result<Vec<String>, E>
for some reasonable E
. Here, we reuse the io::Result
type alias.
Use the lines()
iterator. The other thing you can do is read the whole file into a String
and return that; there's a lines()
iterator for strings as well.
This one you can't do anything about: file_contents
owns its contents, and you can't split them up into multiple, owned String
s. The only thing you can do is borrow the contents of each line, then convert that into a new String
. That said, the way you've put this implies that you believe creating a &str
is expensive; it isn't. It's literally just computing a pair of offsets and returning those. A &str
slice is effectively equivalent to (*const u8, usize)
.
Here's a modified version which does basically the same thing:
use std::fs::File;
use std::io::{self, BufRead};
use std::path::Path;
fn lines_from_file<P>(filename: P) -> io::Result<io::Lines<io::BufReader<File>>>
where
P: AsRef<Path>,
{
let file = File::open(filename)?;
Ok(io::BufReader::new(file).lines())
}
One other change I made: filename
is now a generic P: AsRef<Path>
, because that's what File::open
wants, so it will accept more types without needing conversion.
Upvotes: 22