Reputation: 4244
const int bob = 0;
if(bob)
{
int fred = 6/bob;
}
you will get an error on the line where the divide is done: "error C2124: divide or mod by zero"
which is lame, because it is just as inevitable that the 'if' check will fail, as it is the divide will result in a div by 0. quite frankly I see no reason for the compiler to even evaluate anything in the 'if', except to assure brace integrity.
anyway, obviously that example isn't my problem, my problem comes when doing complicated template stuff to try and do as much at compile time as possible, in some cases arguments may be 0.
is there anyway to fix this error? or disable it? or any better workarounds than this:
currently the only work around I can think of (which I've done before when I encountered the same problem with recursive enum access) is to use template specialization to do the 'if'.
Oh yeah, I'm using Visual Studio Professional 2005 SP1 with the vista/win7 fix.
Upvotes: 9
Views: 2227
Reputation: 179779
The problem - and the compiler has no choice in this - is that bob
is a Integral Constant Expression, as is 6. Therefore 6/bob is also an ICE, and must be evaluated at compile time.
There's a very simple solution: inline int FredFromBob(int bob) { return 6/bob; }
- a function call expression is never an ICE, even if the function is trivial and declared inline.
Upvotes: 3
Reputation: 5732
Can you provide more detail on what you're trying to do with templates? Perhaps you can use a specialised template for 0 that does nothing like in the good old Factorial example and avoid the error altogether.
template <int N>
struct Blah
{
enum { value = 6 / N };
};
template <>
struct Blah<0>
{
enum { value = 0 };
};
Upvotes: 3
Reputation: 67127
I suppose your compiler tries to optimize the code snippet since bob
is defined const
, so that the initial value of fred
can be determined at compile time. Maybe you can prevent this optimization by declaring bob non-const or using the volatile
keyword.
Upvotes: 4