Reputation: 1025
I have a table with the following columns:
A B C --------- 1 10 X 1 11 X 2 15 X 3 20 Y 4 15 Y 4 20 Y
I want to group the data based on the B and C columns and count the distinct values of the A column. But if there are two ore more rows where the value on the A column is the same I want to get the maximum value from the B column.
If I do a simple group by the result would be:
B C Count -------------- 10 X 1 11 X 1 15 X 1 20 Y 2 15 Y 1
What I want is this result:
B C Count -------------- 11 X 1 15 X 1 20 Y 2
Is there any query that can return this result. Server is SQL Server 2005.
Upvotes: 0
Views: 373
Reputation: 4066
Check this out. This should work in Oracle, although I haven't tested it;
select count(a), BB, CC from
(
select a, max(B) BB, Max(C) CC
from yourtable
group by a
)
group by BB,CC
Upvotes: 0
Reputation:
WITH cteA AS
(
SELECT
A, C,
MAX(B) OVER(PARTITION BY A, C) [Max]
FROM T1
)
SELECT
[Max] AS B, C,
COUNT(DISTINCT A) AS [Count]
FROM cteA
GROUP BY C, [Max];
Upvotes: 0
Reputation: 41827
I have actually tested this:
SELECT
MAX( B ) AS B,
C,
Count
FROM
(
SELECT
B, C, COUNT(DISTINCT A) AS Count
FROM
t
GROUP BY
B, C
) X
GROUP BY C, Count
and it gives me:
B C Count
---- ---- --------
15 X 1
15 y 1
20 y 2
Upvotes: 2
Reputation: 3663
I like to work in steps: first get rid of duplicate A records, then group. Not the most efficient, but it works on your example.
with t1 as (
select A, max(B) as B, C
from YourTable
group by A, C
)
select count(A) as CountA, B, C
from t1
group by B, C
Upvotes: 2