Reputation: 12646
I am using a table with alternate row color with this.
tr.d0 td {
background-color: #CC9999;
color: black;
}
tr.d1 td {
background-color: #9999CC;
color: black;
}
<table>
<tr class="d0">
<td>One</td>
<td>one</td>
</tr>
<tr class="d1">
<td>Two</td>
<td>two</td>
</tr>
</table>
Here I am using class for tr
, but I want to use only for table
. When I use class for table than this apply on tr
alternative.
Can I write my HTML like this using CSS?
<table class="alternate_color">
<tr><td>One</td><td>one</td></tr>
<tr><td>Two</td><td>two</td></tr>
</table>
How can I make the rows have "zebra stripes" using CSS?
Upvotes: 580
Views: 909250
Reputation: 73392
$(document).ready(function()
{
$("tr:odd").css({
"background-color":"#000",
"color":"#fff"});
});
tbody td {
padding: 30px;
}
tbody tr:nth-child(odd) {
background-color: #4C8BF5;
color: #fff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table border="1">
<tbody>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
</tr>
<tr>
<td>5</td>
<td>6</td>
<td>7</td>
<td>8</td>
</tr>
<tr>
<td>9</td>
<td>10</td>
<td>11</td>
<td>13</td>
</tr>
</tbody>
</table>
There is a CSS selector, really a pseudo-selector, called nth-child. In pure CSS you can do the following:
tr:nth-child(even) {
background-color: #000000;
}
Note: No support in IE 8.
Or, if you have jQuery:
$(document).ready(function()
{
$("tr:even").css("background-color", "#000000");
});
Upvotes: 853
Reputation: 10961
Here is how it works and how you can for example use the modulo to alternate between rows of several different colors (here 3):
ol>li:nth-child(3n+1) {
background-color: blue;
}
ol>li:nth-child(3n+2) {
background-color: green;
}
/* The following selector is equivalent to "nth-child(3n)" */
ol>li:nth-child(3n+3) {
background-color: red;
}
<ol>
<li />
<li />
<li />
<li />
<li />
<li />
<li />
<li />
<li />
</ol>
As it as already been stated, rows indexes used in the selector starts from 1 (and not 0). That's why the selector of the 1st, 4th, 7th rows is nth-child(3n+1)
.
The selector nth-child(Mn+k)
for a row of index i
reads as if (i % M == k)
. For example, if we want to select all rows whose base 3 modulo is equal to 2 we would write in CSS nth-child(3n+2)
, in other (javascript) words, the selector does this:
const M = 3;
const k = 2;
for (let i = 1; i < 10; i+=1){
// The `nth-child(Mn+k)` selector:
if (i % M == k){
console.log(`${i} selected`);
}
}
Outputs
2 selected
5 selected
8 selected
Upvotes: 2
Reputation: 31
There is a fairly easy way to do this in PHP, if I understand your query, I assume that you code in PHP and you are using CSS and javascript to enhance the output.
The dynamic output from the database will carry a for loop to iterate through results which are then loaded into the table. Just add a function call to the like this:
echo "<tr style=".getbgc($i).">"; //this calls the function based on the iteration of the for loop.
then add the function to the page or library file:
function getbgc($trcount)
{
$blue="\"background-color: #EEFAF6;\"";
$green="\"background-color: #D4F7EB;\"";
$odd=$trcount%2;
if($odd==1){return $blue;}
else{return $green;}
}
Now this will alternate dynamically between colors at each newly generated table row.
It's a lot easier than messing about with CSS that doesn't work on all browsers.
Hope this helps.
Upvotes: 3
Reputation: 382899
can i write my html like this with use css ?
Yes you can but then you will have to use the :nth-child()
pseudo selector (which has limited support though):
table.alternate_color tr:nth-child(odd) td{
/* styles here */
}
table.alternate_color tr:nth-child(even) td{
/* styles here */
}
Upvotes: 15
Reputation: 4671
Please try this way: it can use in Html file for WebView
<head>
<style>
table {
border-collapse: collapse;
width: 100%;
}
th, td {
text-align: left;
padding: 8px;
}
tr:nth-child(even) {
background-color: Lightgreen;
}
</style>
</head>
Upvotes: 0
Reputation: 146640
You have the :nth-child()
pseudo-class:
table tr:nth-child(odd) td{
...
}
table tr:nth-child(even) td{
...
}
In the early days of :nth-child()
its browser support was kind of poor. That's why setting class="odd"
became such a common technique. In late 2013 I'm glad to say that IE6 and IE7 are finally dead (or sick enough to stop caring) but IE8 is still around — thankfully, it's the only exception.
Upvotes: 260
Reputation: 12740
We can use odd and even CSS rules and jQuery method for alternate row colors
Using CSS
table tr:nth-child(odd) td{
background:#ccc;
}
table tr:nth-child(even) td{
background:#fff;
}
Using jQuery
$(document).ready(function()
{
$("table tr:odd").css("background", "#ccc");
$("table tr:even").css("background", "#fff");
});
table tr:nth-child(odd) td{
background:#ccc;
}
table tr:nth-child(even) td{
background:#fff;
}
<table>
<tr>
<td>One</td>
<td>one</td>
</tr>
<tr>
<td>Two</td>
<td>two</td>
</tr>
</table>
Upvotes: 15
Reputation: 7908
Most of the above codes won't work with IE version. The solution that works for IE+ other browsers is this.
<style type="text/css">
tr:nth-child(2n) {
background-color: #FFEBCD;
}
</style>
Upvotes: 10
Reputation: 748
Just add the following to your html code (withing the <head>
) and you are done.
HTML:
<style>
tr:nth-of-type(odd) {
background-color:#ccc;
}
</style>
Easier and faster than jQuery examples.
Upvotes: 58
Reputation: 176956
<script type="text/javascript">
$(function(){
$("table.alternate_color tr:even").addClass("d0");
$("table.alternate_color tr:odd").addClass("d1");
});
</script>
Upvotes: 9
Reputation: 78687
You can use nth-child(odd/even) selectors however not all browsers (ie 6-8, ff v3.0) support these rules hence why most solutions fall back to some form of javascript/jquery solution to add the classes to the rows for these non compliant browsers to get the tiger stripe effect.
Upvotes: 4