Reputation: 19402
In IPython 3 interactive shell:
In [53]: set2 = {1, 2, True, "hello"}
In [54]: len(set2)
Out[54]: 3
In [55]: set2
Out[55]: {'hello', True, 2}
Is that because 1 and True get the same interpetation so given that set eliminates duplicates, only one of them (True) gets to stay? How can we keep both?
Upvotes: 12
Views: 1699
Reputation: 197
Here is an example of how the mechanism of sets to get distinct values works:
def get_distinct_values(values):
set_of_values = set()
for value in values:
hash_value = hash(value)
set_of_values.update([value])
return set_of_values
get_distinct_values([1,2,True,False,int(0.5)])
Output:
{False, 1, 2}
Upvotes: 0
Reputation: 4496
A set is a collection of hashables. Even though the statement 1 is True
is False, the statement 1 == True
is True. Because of that, they have the same hash value and cannot exist separately in a set, and you cannot keep them both in a set
EDIT To make it explicit, as jme pointed out, it is because BOTH things are true - they are equal (per __eq__
) AND they have the same hash value (per __hash__
).
In a perfect world, equal objects would also have the same hash value, and thankfully this is true for built-in types.
Upvotes: 13