Reputation: 4540
I want to build a Lambda Expression using Linq Expressions that is able to access an item in a 'property bag' style Dictionary using a String index. I am using .Net 4.
static void TestDictionaryAccess()
{
ParameterExpression valueBag = Expression.Parameter(typeof(Dictionary<string, object>), "valueBag");
ParameterExpression key = Expression.Parameter(typeof(string), "key");
ParameterExpression result = Expression.Parameter(typeof(object), "result");
BlockExpression block = Expression.Block(
new[] { result }, //make the result a variable in scope for the block
Expression.Assign(result, key), //How do I assign the Dictionary item to the result ??????
result //last value Expression becomes the return of the block
);
// Lambda Expression taking a Dictionary and a String as parameters and returning an object
Func<Dictionary<string, object>, string, object> myCompiledRule = (Func<Dictionary<string, object>, string, object>)Expression.Lambda(block, valueBag, key).Compile();
//-------------- invoke the Lambda Expression ----------------
Dictionary<string, object> testBag = new Dictionary<string, object>();
testBag.Add("one", 42); //Add one item to the Dictionary
Console.WriteLine(myCompiledRule.DynamicInvoke(testBag, "one")); // I want this to print 42
}
In the above test method, I want to assign the Dictionary item value i.e. testBag["one"] into the result. Note that I have assigned the passed in Key string into the result to demonstrate the Assign call.
Upvotes: 12
Views: 7732
Reputation: 53709
You can use the following to access the Item property of the Dictionary
Expression.Property(valueBag, "Item", key)
Here is the code change that should do the trick.
ParameterExpression valueBag = Expression.Parameter(typeof(Dictionary<string, object>), "valueBag");
ParameterExpression key = Expression.Parameter(typeof(string), "key");
ParameterExpression result = Expression.Parameter(typeof(object), "result");
BlockExpression block = Expression.Block(
new[] { result }, //make the result a variable in scope for the block
Expression.Assign(result, Expression.Property(valueBag, "Item", key)),
result //last value Expression becomes the return of the block
);
Upvotes: 19