What is the difference between Optional.flatMap and Optional.map?

Question

What's the difference between these two methods: Optional.flatMap() and Optional.map()?

An example would be appreciated.

Answer 1

NOTE

Below is the illustration of map() and flatMap() functions, otherwise Optional is primarily designed to be used as a return type only.

---

As you already may know Optional is a kind of container which may or may not contain a single object, so it can be used wherever you anticipate a null value (you may never see NPE if you use Optional properly).

For example if you have a method which expects a Person object which may be nullable you may want to write the method something like this:

void doSome(Optional<Person> person) {
    /* and here you want to retrieve some property phone out of person
       you may write something like this:
    */
    Optional<String> phone = person.map((p) -> p.getPhone());
    phone.ifPresent((ph) -> dial(ph));
}

class Person {
    private String phone;
    // setters, getters
}

Here you have returned a String type which is automatically wrapped in an Optional type.

If Person class looked like this (i.e. phone is also Optional):

class Person {
    private Optional<String> phone;
    // setters, getters
}

In this case invoking map() function will wrap the returned value in Optional and yield something like:

Optional<Optional<String>>

But you may want Optional<String> instead, so here comes flatMap():

void doSome(Optional<Person> person) {
    Optional<String> phone = person.flatMap((p) -> p.getPhone());
    phone.ifPresent((ph) -> dial(ph));
}

---

P.S.

Never call get() method (if you need to) on an Optional without checking it with isPresent() unless you can't live without NullPointerException.

Answer 2

• Optional.map():

Takes every element and if the value exists, it is passed to the function:

Optional<T> optionalValue = ...;
Optional<Boolean> added = optionalValue.map(results::add);

Now added has one of three values: true or false wrapped into an Optional , if optionalValue was present, or an empty Optional otherwise.

If you don't need to process the result you can simply use ifPresent(), it doesn't have return value:

optionalValue.ifPresent(results::add); 

• Optional.flatMap():

Works similar to the same method of streams. Flattens out the stream of streams. With the difference that if the value is presented it is applied to function. Otherwise, an empty optional is returned.

You can use it for composing optional value functions calls.

Suppose we have methods:

public static Optional<Double> inverse(Double x) {
    return x == 0 ? Optional.empty() : Optional.of(1 / x);
}

public static Optional<Double> squareRoot(Double x) {
    return x < 0 ? Optional.empty() : Optional.of(Math.sqrt(x));
}

Then you can compute the square root of the inverse, like:

Optional<Double> result = inverse(-4.0).flatMap(MyMath::squareRoot);

or, if you prefer:

Optional<Double> result = Optional.of(-4.0)
                     .flatMap(MyMath::inverse)
                     .flatMap(MyMath::squareRoot);

If either the inverse() or the squareRoot() returns Optional.empty(), the result is empty.

Answer 3

They do the same thing.

The only difference is that, the lambda return's type is wrapped by Optional or not.

For normal usage, map is shorter than flatMap

Example:

package bj;

import java.util.Optional;

import static java.lang.System.out;

public class App {

    public static void main(String[] args) {
        out.println(Optional.of(10).map    (x ->             x * x));
        out.println(Optional.of(10).flatMap(x -> Optional.of(x * x)));
        out.println(Optional.of(10).map    (x -> Optional.of(x * x).get()));

        out.println(Optional.<Integer>empty().map    (x ->             x * x));
        out.println(Optional.<Integer>empty().flatMap(x -> Optional.of(x * x)));
        out.println(Optional.<Integer>empty().map    (x -> Optional.of(x * x).get()));
    }
}

Output:

Optional[100]
Optional[100]
Optional[100]
Optional.empty
Optional.empty
Optional.empty

Answer 4

You can refer below link to understand in detail (best explanation which I could find):

https://www.programmergirl.com/java-8-map-flatmap-difference/

Both map and flatMap - accept Function. The return type of map() is a single value whereas flatMap is returning stream of values

<R> Stream<R> map(Function<? super T, ? extends R> mapper)

<R> Stream<R> flatMap(Function<? super T, ? extends Stream<? extends R>> mapper)

Answer 5

Okay. You only need to use 'flatMap' when you're facing nested Optionals. Here's the example.

public class Person {

    private Optional<Car> optionalCar;

    public Optional<Car> getOptionalCar() {
        return optionalCar;
    }
}

public class Car {

    private Optional<Insurance> optionalInsurance;

    public Optional<Insurance> getOptionalInsurance() {
        return optionalInsurance;
    }
}

public class Insurance {

    private String name;

    public String getName() {
        return name;
    }

}

public class Test {

    // map cannot deal with nested Optionals
    public Optional<String> getCarInsuranceName(Person person) {
        return person.getOptionalCar()
                .map(Car::getOptionalInsurance) // ① leads to a Optional<Optional<Insurance>
                .map(Insurance::getName);       // ②
    }

}

Like Stream, Optional#map will return a value wrapped by a Optional. That's why we get a nested Optional -- Optional<Optional<Insurance>. And at ②, we want to map it as an Insurance instance, that's how the tragedy happened. The root is nested Optionals. If we can get the core value regardless the shells, we'll get it done. That's what flatMap does.

public Optional<String> getCarInsuranceName(Person person) {
    return person.getOptionalCar()
                 .flatMap(Car::getOptionalInsurance)
                 .map(Insurance::getName);
}

In the end, I stronly recommed the Java 8 In Action to you if you'd like to study Java8 Systematicly.

Answer 6

They both take a function from the type of the optional to something.

map() applies the function "as is" on the optional you have:

if (optional.isEmpty()) return Optional.empty();
else return Optional.of(f(optional.get()));

What happens if your function is a function from T -> Optional<U>?
Your result is now an Optional<Optional<U>>!

That's what flatMap() is about: if your function already returns an Optional, flatMap() is a bit smarter and doesn't double wrap it, returning Optional<U>.

It's the composition of two functional idioms: map and flatten.

Answer 7

What helped me was a look at the source code of the two functions.

Map - wraps the result in an Optional.

public<U> Optional<U> map(Function<? super T, ? extends U> mapper) {
    Objects.requireNonNull(mapper);
    if (!isPresent())
        return empty();
    else {
        return Optional.ofNullable(mapper.apply(value)); //<--- wraps in an optional
    }
}

flatMap - returns the 'raw' object

public<U> Optional<U> flatMap(Function<? super T, Optional<U>> mapper) {
    Objects.requireNonNull(mapper);
    if (!isPresent())
        return empty();
    else {
        return Objects.requireNonNull(mapper.apply(value)); //<---  returns 'raw' object
    }
}

Answer 8

Use map if the function returns the object you need or flatMap if the function returns an Optional. For example:

public static void main(String[] args) {
  Optional<String> s = Optional.of("input");
  System.out.println(s.map(Test::getOutput));
  System.out.println(s.flatMap(Test::getOutputOpt));
}

static String getOutput(String input) {
  return input == null ? null : "output for " + input;
}

static Optional<String> getOutputOpt(String input) {
  return input == null ? Optional.empty() : Optional.of("output for " + input);
}

Both print statements print the same thing.