CODEWITHSUNDEEP
bash
Crista23
Crista23

Reputation: 3243

Bash - convert string to date

I need to convert to date in bash a string which has the hour included, such as: 2012-02-09-18, and store the result inside a variable, so that I can compare such strings as dates. If I use for conversion

  date -d "2012-02-09-18"

it will crash with "Invalid date error". How can I do this?

Upvotes: 2

Views: 297

Answers (2)

Cyrus
Cyrus

Reputation: 88601

Try this with bash's parameter expansion:

a="2012-02-09-18"
date -d "${a%-*} ${a#*-*-*-*}"

Output:

Thu Feb  9 18:00:00 CET 2012

Upvotes: 4

anubhava
anubhava

Reputation: 785146

You can tweak input to make it parseable by date using sed:

str='2012-02-09-18'

date -d "$(sed 's/-\([^-]*\)$/ \1/' <<< "$str")"
Thu Feb  9 18:00:00 EST 2012

Upvotes: 3

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