CODEWITHSUNDEEP
javascriptmatrixthree.jslinear-algebramatrix-multiplication
Nathan Friend
Nathan Friend

Reputation: 12834

What does three.js's Matrix4.multiply() method do?

I'm learning three.js and am trying to multiply two translation matrices together to get a single matrix that describes both translations:

| 1 0 0 -2 |   | 1 0 0 3 |
| 0 1 0  7 | * | 0 1 0 4 |
| 0 0 1  6 |   | 0 0 1 6 |
| 0 0 0  1 |   | 0 0 0 1 |

I was expecting the following matrix:

| 1 0 0  1 |   
| 0 1 0 11 | 
| 0 0 1 12 |   
| 0 0 0  1 |

But instead, I'm getting this matrix:

| 1  0  0  0 |   
| 0  1  0  0 | 
| 0  0  1  0 |   
| 1  11 12 1 |

I'm using three.js's Matrix4.multiply() method to do the multiplication:

var result = matrix1.multiply(matrix2);

Here's a jsfiddle that shows this in action.

And here's a WolframAlpha query that gives the expected result.

I'm obviously misunderstanding three.js's Matrix4.multiply() method. What is this method doing and how can I instead achieve the expected behavior?

Upvotes: 4

Views: 4937

Answers (1)

ericbn
ericbn

Reputation: 10998

The problem is in how you're iterating the matrix elements to print them. The .elements property returns the elements in column-major order (despite the constructor and .set() methods parameters being in row-major order!). So you should:

function logMatrix(matrix) {
    var e = matrix.elements;
    var $output = $('#output');
    $output.html(e[0] + ' ' + e[4] + ' ' + e[8] + ' ' + e[12] + '\n');
    $output.append(e[1] + ' ' + e[5] + ' ' + e[9] + ' ' + e[13] + '\n');
    $output.append(e[2] + ' ' + e[6] + ' ' + e[10] + ' ' + e[14] + '\n');
    $output.append(e[3] + ' ' + e[7] + ' ' + e[11] + ' ' + e[15] + '\n');
}

Also note that there was a typo in your code and you were printing e[13] twice...

Upvotes: 3

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