CODEWITHSUNDEEP
performancepython-3.x
ParaH2
ParaH2

Reputation: 517

Time of execution in Python 3.3

I read this topic because I forget a method I found in the net few month ago, and I don't know why I can't find it today, it was very simple and works good but...

So I tried one method but I think it doesn't work good or maybe my computer which is 5 years old is better than today's computer... 

import time

debut=time.clock()

def t(n): 
    aaa=[]
    b=n-1
    c=0
    if n==0 or n==1:
        return 1
    else:
        while n != 1: 
            if n % 2==0: 
                n=n//2
                aaa.append(n)
            else: 
                n = n+b
                aaa.append(n)
    return [b,b+1]+aaa, len(aaa)+2

fin=time.clock()

print(t(100000),fin-debut)

For n=10.000.000 i can count in my head approx 5 secondes and computer always return 3.956927685067058e-06 ... can someone explain me ?

And the method I found, used this from time import perf_counter as pc

And I had to return print(pc()-t)

If someone can enlighten me because i really don't remember the method.

Thank you in advance

Upvotes: 0

Views: 100

Answers (2)

Mitch
Mitch

Reputation: 193

Look at the timeit module, https://docs.python.org/3.0/library/timeit.html.

you would set yours something like...

time = Timer( "t(100000)", "from __main__ import t")
print("time: ", timer.timeit(number=1000))

Upvotes: 2

User
User

Reputation: 14853

You are measuring the time it takes to define the function. This will measure the execution of the function:

import time

def t(n): 
    aaa=[]
    b=n-1
    c=0
    if n==0 or n==1:
        return 1
    else:
        while n != 1: 
            if n % 2==0: 
                n=n//2
                aaa.append(n)
            else: 
                n = n+b
                aaa.append(n)
    return [b,b+1]+aaa, len(aaa)+2

start = time.time()
value = t(100000)
end = time.time()

duration = end - start
print(value, duration)

Upvotes: 0

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