Reputation: 1418
I have a plot() where multiple colour shadings represent the same thing. I would like to add a legend that conveys this by having dual-coloured boxes (see example below). Is there any way to do this using legend() or a similar command? Alternatively, is there a way to identify the precise coordinates of these boxes so I can plot a polygon() triangle over it?
Note: legend() does return the coordinates of the outer box and the top left of each labels, but I am not sure if this is sufficient to calculate where the coloured boxes are.
Upvotes: 0
Views: 1537
Reputation: 1418
A slightly dirty hack can allow you to get the legend()
function to give you the necessary information. A smarter person than me would probably work out how legend()
calculates box positioning and replicate this outside the function. Note that editing standard R functions is probably not recommended.
If you have not edited R functions yet, an easy (and temporary) way to access it, is typing
fix(legend)
Typing
rm(legend)
later will undo your changes.
Find this section that says fill <- rep
and add the lines indicated by the comments:
fillList <- NULL ## added
if (mfill) {
if (plot) {
fill <- rep(fill, length.out = n.leg)
rect2(left = xt, top = yt + ybox/2, dx = xbox, dy = ybox,
col = fill, density = density, angle = angle,
border = border)
fillList <- data.frame(left = xt, top = yt + ybox/2, dx = xbox, dy = ybox) ## added
}
xt <- xt + dx.fill
}
Find the very last line and change it to
invisible(list(rect = list(w = w, h = h, left = left, top = top),
text = list(x = xt, y = yt), fillList=fillList)) ## modified
Now call legend via
output <- legend(...) ## replace ... with whatever you want to have as inputs
and the draw triangles using the information returned by legend()
like so:
with(output$fillList[1,], { ## first box
polygon(c(left, left+dx, left+dx), c(top, top, top-dy), col=myColour, border=NA)
})
Upvotes: 0
Reputation: 16277
This is a bit of a hack, but you could put two legends on top of another. Unfortunately, there is no left triangle pch
which would have been exactly as you wanted.
plot(1)
legend("bottomright",c("Label 1", "Label 2"),pch=22,col=c("red","blue"),pt.bg=c("red","blue"), pt.cex=1.8)
legend("bottomright",c("Label 1", "Label 2"),pch=21,col=c("green","orange"),pt.bg=c("green","orange"))
Upvotes: 1