Reputation: 420
Say I have this pseudocode in bash
#!/bin/bash
things
for i in {1..3}
do
nohup someScript[i] &
done
wait
for i in {4..6}
do
nohup someScript[i] &
done
wait
otherThings
and say this someScript[i] sometimes end up hanging.
Is there a way I can take the process IDs (with $!) and check periodically if the process is taking more than a specified amount of time after which I want to kill the hanged processes with kill -9 ?
Upvotes: 1
Views: 2694
Reputation: 420
Unfortunately the answer from @Eugeniu did not work for me, timeout gave an error.
Create another script which goes like this
#!/bin/bash
#monitor.sh
pid=$1
counter=10
while ps -p $pid > /dev/null
do
if [[ $counter -eq 0 ]] ; then
kill -9 $pid
#if it's still there then kill it
fi
counter=$((counter-1))
sleep 1
done
then in the main work you just put
things
for i in {1..3}
do
nohup someScript[i] &
./monitor.sh $! &
done
wait
In this way for any of your someScript you will have a parallel process that checks if it's still there every chosen interval (until maximum time decided by the counter) and that actually quit itself if the associated process dies (or gets killed)
Upvotes: 1
Reputation: 5315
One possible approach:
#!/bin/bash
# things
mypids=()
for i in {1..3}; do
# launch the script with timeout (3600s)
timeout 3600 nohup someScript[i] &
mypids[i]=$! # store the PID
done
wait "${mypids[@]}"
Upvotes: 0