Reputation: 7894
I have XML like this:
<assessment name="Assessment">
<section name="Section1">
<item name="Item1-1"/>
<item name="Item1-2"/>
<item name="Item1-3"/>
<item name="Item1-4"/>
<item name="Item1-5"/>
</section>
<section name="Section2">
<item name="Item2-1"/>
<item name="Item2-2"/>
<item name="Item2-3"/>
<section name="Section2-2">
<item name="Item2-2-1"/>
<item name="Item2-2-2"/>
<item name="Item2-2-3"/>
<item name="Item2-2-4"/>
</section>
</section>
</assessment>
As you can see, an assessment can contain sections. A section can contain sections and/or items.
I want to use XSLT to recursively count the number of items in assessments and sections. So, my transformation should output something like this:
Assessment: 12 items
Section1: 5 items
Section2: 7 items
Section2-2: 4 items
I have a start with this recursive XSLT:
<stylesheet version="2.0" xmlns="http://www.w3.org/1999/XSL/Transform"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<output method="text"/>
<template match="/assessment">
<xsl:for-each select="section">
<xsl:call-template name="sectionCount">
</xsl:call-template>
</xsl:for-each>
</template>
<template name="sectionCount">
<xsl:variable name="items" select="item"/>
<xsl:for-each select="section">
<xsl:call-template name="sectionCount">
</xsl:call-template>
</xsl:for-each>
<xsl:value-of select="count($items)"/>
</template>
</stylesheet>
What I can't figure out how to do is pass the values back up and add them. How is this done, exactly?
Upvotes: 2
Views: 1635
Reputation: 243529
Here is an XSLT 2.0 solution
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:my="my:my"
>
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:template match="assessment|section">
<xsl:value-of select="concat(@name, ': ', my:sumItems(.), ' items
')"/>
<xsl:apply-templates/>
</xsl:template>
<xsl:function name="my:sumItems" as="xs:integer*">
<xsl:param name="pNode" as="element()"/>
<xsl:sequence select="count($pNode/item) + sum($pNode/section/my:sumItems(.))"/>
</xsl:function>
</xsl:stylesheet>
when this transformation is applied on the provided XML document:
<assessment name="Assessment">
<section name="Section1">
<item name="Item1-1"/>
<item name="Item1-2"/>
<item name="Item1-3"/>
<item name="Item1-4"/>
<item name="Item1-5"/>
</section>
<section name="Section2">
<item name="Item2-1"/>
<item name="Item2-2"/>
<item name="Item2-3"/>
<section name="Section2-2">
<item name="Item2-2-1"/>
<item name="Item2-2-2"/>
<item name="Item2-2-3"/>
<item name="Item2-2-4"/>
</section>
</section>
</assessment>
the wanted, correct result is produced:
Assessment: 12 items
Section1: 5 items
Section2: 7 items
Section2-2: 4 items
While in this particular problem one could use a straightforward XPath expression (count(.//item)
), this solution demonstrates a generall and useful pattern for problems that don't allow such immediate calculation.
Upvotes: 0
Reputation: 11986
To answer your question: you wrap the call to the template(s) in a variable declaration.
<xsl:variable name="result">
<!-- call or apply templates here -->
<xsl:call-template name="my-template"/>
</xsl:variable>
<!-- use the defined value: -->
<xsl:copy-of select="$result"/>
However there is, in your case a better way to get total number of items arbitrarily deep in the nested structure: use XPath wildcards:
<xsl:value-of select="count(.//item)"/>
You can use this like so:
<xsl:template match="assessment|section">
<!-- output section subtotal -->
<!-- print name : number-of-items, adapt to get the proper section name -->
<xsl:value-of select="concat(@name, ': ', count(.//item))"/>
<!-- recurse: sub sections will get their subtotals listed, too -->
<xsl:apply-templates select="*"/>
</xsl:template>
Upvotes: 1