CODEWITHSUNDEEP
phpparsingurlparametersquery-string
Jeffrey Spiteri
Jeffrey Spiteri

Reputation: 11

How can you remove last parameter from a $_GET URL when using the QUERY_STRING?

Since I'm using a foreach loop, all the parameters are shown. I have several parameters which I want to include from my URL, but I want to remove the last parameter and it's value from automatically showing. The code is as follows:

 <?php   

$query  = explode('&', $_SERVER['QUERY_STRING']);
$params = array();

foreach( $query as $param )
{ 
  list($name, $value) = explode('=', $param, 2);
  echo $params[urldecode($name)][] = urldecode($value);
  echo "<br/>";
}

  echo "<br/> Total amount placed: ".$total = $_GET["total"];

?>

The URL is this one:

confirmation.php?betSlip=Juve&betSlip=Milan&total=0.43

As you can see the url consists of several items inside a betSlip parameter, and it consists the total of all items. I want to remove the total from displaying in the foreach loop and be able to display it only whenever I call it.

Thanks

Upvotes: 1

Views: 854

Answers (2)

Caleb Loffer
Caleb Loffer

Reputation: 11

DavidDomain is right. You could alternatively unset just that specific key value pair in the array, if you can't guarantee it'll always be the last array element.

$params = $_GET;

unset($params['total']);

// $params is now array('betSlip' => 'Juve', 'betSlip' => 'Milan');

Upvotes: 1

DavidDomain
DavidDomain

Reputation: 15293

Just use array_pop to remove the last element of the $query array. Given that total will always be the last param.

    $params = "betSlip=Juve&betSlip=Milan&total=0.43";
    $query  = explode('&', $params);
    array_pop($query); // remove the last element of $query
    $params = array();

    foreach( $query as $param )
    {
        list($name, $value) = explode('=', $param, 2);
        echo $params[urldecode($name)][] = urldecode($value);
        echo "<br/>";
    }

    echo "<br/> Total amount placed: ".$total = $_GET["total"];

Upvotes: 0

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