Reputation: 77
I want to regex thread_id in this html code by using php
<a id="change_view" class="f_right" href="pm.php?view=chat&thread_id=462075438105382912">
I wrote this code however it return empty array to me
$success = preg_match_all('/pm\.php\?view=chat&thread_id=([^"]+)/', $con, $match2);
is there any problem in my php code ?
Upvotes: 0
Views: 54
Reputation: 559
if (preg_match('/thread_id=[0-9]*/', $line, $matches))
$thread_id = $matches[0];
Upvotes: 0
Reputation: 8652
Well, you said it is giving you an empty array. But it is not. Here is the value returned by print_r()
Array
(
[0] => Array
(
[0] => pm.php?view=chat&thread_id=462075438105382912
)
[1] => Array
(
[0] => 462075438105382912
)
)
But It is not returning what you want it to. The regular expression to get string that comes after thread_id=
and before &
or "
is :
/(?<=thread_id=).*(?=\"|&)/
Working example :
<?php
$con = '<a id="change_view" class="f_right" href="pm.php?view=chat&thread_id=462075438105382912">link</a>';
$match2 = Array();
preg_match_all('/(?<=thread_id=).*(?=\"|&)/', $val, $arr);
echo "<pre>";
print_r($arr);
echo "</pre>";
?>
Output :
Array
(
[0] => Array
(
[0] => 462075438105382912
)
)
Upvotes: 1
Reputation: 1167
If you're only looking for the thread_id, this should do it.
$success = preg_match_all('/(thread_id=)([\d]+)/', $con, $match2);
Upvotes: 0