CODEWITHSUNDEEP
python-3.x
Sal Meza
Sal Meza

Reputation: 11

How to remove ending commas in a list of ints with python?

I have a function I wrote in python that simple makes a horizontal list of int. I modified the print statement so that the list would print with commas, but the function adds one after the last int.

Any ideas as how to get rid of it?

num = list(range(20))

def count(x):
    for i in range(len(x)):
        # i+1 add in order to remove beginning zero.
        print(i+1,end=',')

count(num)

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,

Upvotes: 1

Views: 1727

Answers (5)

drPete
drPete

Reputation: 101

Rather than creating a function, an output sequence can be processed with the range command:

num   = range(1,21,1)
print num

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

Print without the braces:

num = range(1,21,1)
print str(num).strip('[]')

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20

User chooses start and ending numbers somewhere earlier in the code:

start = 56
end   = 69
num   = range(start, end + 1)
print str(num).strip('[]')

Output is:

56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69

User supplies start and stop interactivly:

start = raw_input('Choose start')
end   = raw_input('Choose end')
num   = range(start, end + 1)
print str(num).strip('[]')

Upvotes: 0

Ethan Furman
Ethan Furman

Reputation: 69031

A better function name would be display, and the function you want is str.join():

def display(list_data):
    print(', '.join(list_data))

The thing to keep in mind is the pieces to join must be strings, so you may need to convert:

', '.join([str(i) for i in list_data])

Upvotes: 0

Phill Treddenick
Phill Treddenick

Reputation: 1420

Add each number to a string and then print the string minus the last character:

   num = list(range(20))

    def count(x):
        s = ""
        for i in range(len(x)):
            # i+1 add in order to remove beginning zero.
            s += str(i+1) + ","
        print(s[:-1])

    count(num)

Output:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20

Upvotes: 0

Chandan Nayak
Chandan Nayak

Reputation: 10877

Try this:

num = list(range(20))
l = []
def count(x):
    for i in range(len(x)):
        l.append(i+1)

count(num)
print(l)

Outpout:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

You can also modify it to this:

def count(x):
    for i in range(len(x)):
        # i+1 add in order to remove beginning zero.
        if i < len(x)-1:
            print(i+1, end=',')
        else:
            print(i+1)

Output:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20

Upvotes: 2

GAVD
GAVD

Reputation: 2134

Try this:

num = list(range(20))

def count(x):
    for i in range(len(x)-1):
        print(i+1,end=',')
    print(len(x))

count(num)

Upvotes: 0

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