CODEWITHSUNDEEP
scalaintellij-ideasbt
daydreamer
daydreamer

Reputation: 91999

Why does sbt create layers of projects and src in IDEA?

I am new to SBT and trying to build a project. My Build.scala looks like 

  lazy val ec = project.in(file("."))
    .settings(commonSettings: _*)
    .settings(name := "ec")
    .aggregate(ahka, currentLogProcessor, main)

  lazy val currentLogProcessor = project.in(file("currentLogProcessor"))
    .settings(commonSettings: _*)
    .settings(name := "currentlogprocessor")
    .settings(
      libraryDependencies += "com.myorg.util" % "LP" % "0.18.0-SNAPSHOT" % "provided"
    )

  lazy val main = project
    .settings(commonSettings: _*)
    .settings(name := "main")

When SBT refreshes in IntelliJ, I see following

As you could see, even if the settings looks same for currentLogProcessor and main, the project structure is very very different.

project inside currentLogProcessor looks good but project under main is layer with project and src

What is the issue here? How can I remove the layers of project inside project?

Thanks enter image description here

Upvotes: 0

Views: 107

Answers (2)

Jacek Laskowski
Jacek Laskowski

Reputation: 74679

The answer by @ka4eli is correct, but I'd like to point out few issues with the build definition that can make understanding it so much painful.

Defining top-level aggregate project

lazy val ec = project.in(file("."))
    .settings(commonSettings: _*)
    .settings(name := "ec")
    .aggregate(ahka, currentLogProcessor, main)

You don't need it whatsoever as it's defined automatically anyway - you're just repeating what sbt does implicitly. Just remove it from the build and add build.sbt with the following:

commonSettings

Use build.sbt for a project's build definition

lazy val currentLogProcessor = project.in(file("currentLogProcessor"))
    .settings(commonSettings: _*)
    .settings(name := "currentlogprocessor")
    .settings(
      libraryDependencies += "com.myorg.util" % "LP" % "0.18.0-SNAPSHOT" % "provided"
    )

By default, lazy val's name is used to call a project project macro should point to, i.e. no need for in(file("currentLogProcessor")). The same applies to the name setting - you're using all-lowercase name that may or may not be needed.

Use build.sbt under currentLogProcessor directory to have the same effect:

name := "currentlogprocessor"
commonSettings

libraryDependencies += "com.myorg.util" % "LP" % "0.18.0-SNAPSHOT" % "provided"

It's that simple.

Apply the rules to the main project.

Have fun with sbt = it's so simple that people hardly accept it and mess up build definitions on purpose to claim otherwise :)

Upvotes: 0

ka4eli
ka4eli

Reputation: 5424

Your projects ec and main share the same folder. Remove main or ec, or change "in file" for one of them. 

lazy val main = project in file("another_path") ...

Upvotes: 1

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