CODEWITHSUNDEEP
gitbashdategit-commit
user3472065
user3472065

Reputation: 1389

With GIT show commits older than a specific date with specific format

I need to print the latest 10 commits that are older than a specific date with specific format. I need to handle the date, obtained through the bash command:

 date +"%Y%m%d%H%M"

I tried some options, but so far nothing

e.g.: git log -5 --no-merges --format=format:%cd --after=201506301524

Upvotes: 3

Views: 2801

Answers (3)

jofel
jofel

Reputation: 3405

You need to use --until instead of --after and furthermore, the correct date format, but you can use date to convert it:

git log --no-merges --format=format:%cd -10 --until "$(date -d "$(echo "201506301524" | sed 's/....$/ &/')")"

$(echo "201506301524" | sed 's/....$/ &/') converts the date to 20150630 1524 which is a valid input format for date.

Upvotes: 1

zessx
zessx

Reputation: 68790

First, you need to use the right date format (date +"%Y-%m-%d %H:%M:00"):

git log --no-merges --format=format:%cd --after="2015-06-30 15:24:00"

Now, you can use --reverse to get oldest commits first:

git log --reverse --no-merges --format=format:%cd --after="2015-06-30 15:24:00"

Unfortunately, git log --reverse -10 won't return what you want, as it'll grap the 10 latest commits, then reverse the list (which means you'll get the same list, whatever the specified date).

An alternative is to use head on this result:

git log --reverse --no-merges --format=format:%cd --after="2015-06-30 15:24:00" | head -10

Upvotes: 0

Havenard
Havenard

Reputation: 27844

You have to format the date, only numbers won't do. Use one of those:

--after=2015-06-30-15:24:00
--after=2015-06-30:16:24:00
--after="2015-06-30 16:24:00"

All of those formats were accepted.

Upvotes: 2

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