CODEWITHSUNDEEP
amazon-web-servicesflaskamazon-elastic-beanstalk
Pav Sidhu
Pav Sidhu

Reputation: 6954

Your WSGIPath refers to a file that does not exist

I'm trying to upload my Flask application to AWS however I receive an error on doing so:

Your WSGIPath refers to a file that does not exist.

After doing some digging online I found that in the .ebextensions folder, I should specify the path. There was not a .ebextensions folder so I created one and added the following code to a file named settings.config:

option_settings:
  "aws:elasticbeanstalk:container:python":
    WSGIPath: project/application.py

the WSGIPath is the correct path to the application.py file so I'm not sure what raises this error. Am I changing the WSGIPath right, is there a better way or is there an issue with something else which causes this to happen? Thanks.

Upvotes: 46

Views: 39934

Answers (5)

ikonuk
ikonuk

Reputation: 652

In my case trying many solutions didn't solve the issue but changing WSGIPath from 

option_settings:
  "aws:elasticbeanstalk:container:python":
    WSGIPath: project_name/application_name.py

to

option_settings:
      "aws:elasticbeanstalk:container:python":
        WSGIPath: project_name.wsgi

worked like a charm. Here is the file structure:

├── manage.py
├── mysite ***
│   ├── __init__.py
│   ├── settings.py
│   ├── urls.py
│   └── wsgi.py ***
├── myvenv
│   └── ...
└── requirements.txt

Upvotes: 0

Lahiru Jayakody
Lahiru Jayakody

Reputation: 5410

If anyone here is doing via AWS Console (GUI), modify the configuration and put your script name in WSGIPath as below.

enter image description here

I'm giving bonus hints if you are newer.

  • You should match the script name and the Flask object too.
  • Common mistake: When you're compressing the source code, you need to select the files and compress, not the folder. (make sure you have the .py in the root of the zip)
from flask import Flask
application = Flask(__name__)

@application.route("/")
def hello():
    return "Hello"

if __name__ == "__main__":
    application.run()

Upvotes: 11

Chris Merck
Chris Merck

Reputation: 454

For me the problem was I had misspelled a filename:

I wrote: ..ebextensions/django.conf

When I needed: ..ebextensions/django.config

This cost me about 3 hours of my life today. The trouble was that the AWS error is misleading, because the "WSGIPath" it refers to is not the file above, but some invisible default.

Upvotes: 0

Nemanja Radojković
Nemanja Radojković

Reputation: 189

I had the same message, but for a very stupid reason.

Apparently, when I cloned the repo to my Windows PC and then pushed back the changes, somewhere along the way Windows changed ".ebextensions" folder to "ebextensions" (dropping the leading ".").

So when I renamed back the folder to ".ebextensions" in the master repo, everything started working again perfectly.

Upvotes: 1

joshmcode
joshmcode

Reputation: 3642

There's a lot of configuration issues that can arise with Flask deployed on AWS. I was running into a similar issue as you, so I can at least show you what I did to resolve the WSGI error.

First, apparently you can do this without the .ebextensions folder (see this post here. and look at davetw12's answer. However, be aware that while this works, I'm not entirely sure that davetw12's conclusion about .ebextensions is correct, based on some of the comments below). Instead, (in the Terminal), I navigated to my project at the same level as my .elasticbeanstalk directory and used the command eb config. This will open up a list of options you can set to configure your beanstalk application. Go down through the options until you find the WSGI path. I notice you have yours set to project/application.py, however, this should not include the folder reference, just application.py. Here is how it looks on my Mac in the terminal (WSGI path is near the bottom).

enter image description here

Note that once you get that set, EB will probably redeploy. That's fine. Let it.

Once you get that set, go into your application.py file and make sure you call your app application. For example, mine looks like this: 

from flask import Flask
from flask import render_template
application = Flask(__name__)

@application.route('/')
@application.route('/index')
def index():
    return render_template('index.html',
                           title='Home')

This took away the WSGI path error - although I still had to fix some other issues following this :-) But that is a different set of questions.

Upvotes: 46

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