CODEWITHSUNDEEP
javascriptregexurlwildcard
Sam Bowler
Sam Bowler

Reputation: 103

Matching URL with wildcards

I'm trying to match URLs with wildcards in them to actual URLs. For example:

http://*google.com/*

Needs to match

http://maps.google.com

And

http://www.google.com/maps

What would be the best way of going about this?

I've tried using a regular expression and that works fine when I manually program it but I'm not sure whether it's possible to dynamically generate regular expressions or if that would be the best practice in this situation.

/(http|https):\/\/.*\.?google\.com\/?.*/i

Thanks very much.

Upvotes: 6

Views: 17871

Answers (2)

nas
nas

Reputation: 977

If you want to see a well tested library for extracting parts of a URI, I would check out Google Closure Library's goog.uri.utils methods.

https://github.com/google/closure-library/blob/8e44fb343fff467938f9476ba7f727c6acac76d8/closure/goog/uri/utils.js#L187

Here's the regex that does the heavy lifting:

goog.uri.utils.splitRe_ = new RegExp(
    '^' +
    '(?:' +
      '([^:/?#.]+)' +                     // scheme - ignore special characters
                                          // used by other URL parts such as :,
                                          // ?, /, #, and .
    ':)?' +
    '(?://' +
      '(?:([^/?#]*)@)?' +                 // userInfo
      '([\\w\\d\\-\\u0100-\\uffff.%]*)' + // domain - restrict to letters,
                                          // digits, dashes, dots, percent
                                          // escapes, and unicode characters.
      '(?::([0-9]+))?' +                  // port
    ')?' +
    '([^?#]+)?' +                         // path
    '(?:\\?([^#]*))?' +                   // query
    '(?:#(.*))?' +                        // fragment
    '$');

Upvotes: 2

Amarghosh
Amarghosh

Reputation: 59451

Replace all occurrences of * in the pattern with [^ ]* - it matches a sequence of zero or more non-space characters.

Thus http://*google.com/* will become http://[^ ]*google.com/[^ ]*

Here is a regular expression to do the task:

regex = urlPattern.replace(/\*/g, "[^ ]*");

Upvotes: 17

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