CODEWITHSUNDEEP
bashscripting
Bubbles
Bubbles

Reputation: 97

Switch functionality in bash script

While using case statement whose syntax is

      case $variable-name  in

            pattern1)  command;;

            patternN)  command;;

            *)         command;;
       esac

Here " *)" is meant for default case whose patterns doesn’t match for any case. What if I want to match for the pattern " * " and do multiplication and should have default case also?

Upvotes: 1

Views: 121

Answers (2)

iqstatic
iqstatic

Reputation: 2382

You can either escape the * character using \* or if you are doing certain operations such as addition, multiplication, etc. based on the choice of pattern/character it is better to use numbers to indicate the operation. For example:

  1. Addition
  2. Subtraction
  3. Multiplication
  4. Division

So by doing this your case statement can be something like this:

case $variable-name in
    1)sum=$((n1 + $n2))
     echo "Sum = $sum";;
    2)difference=$((n1 - n2))
     echo "Sub = $difference";;
    3)product=$(( n1 * n2 ))
     echo "Mul = $product";;
    4)quotient=$(( n1 / n2 ))
     echo "Div = $quotient";;
    *)echo "Invalid choice";;
esac

Upvotes: 1

Justin Guedes
Justin Guedes

Reputation: 131

Just escape it like so:

#!/bin/bash

variable-name="*"

case $variable-name in
    \*) echo "Star";;
    *) echo "Default";;
esac

Or you could put the * in quotes.

Upvotes: 5

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