CODEWITHSUNDEEP
phparrays
ichadhr
ichadhr

Reputation: 644

PHP array check all values is equal

 array
  0 => 
    array
      'point' => string '2' 
  1 => 
    array 
      'point' => string '4' 
  2 => 
    array 
      'point' => string '1'

I need checking values of 'point' in above array, if all values of 'point' is '4' it will return true as below array.

array
  0 => 
    array
      'point' => string '4'
  1 => 
    array
      'point' => string '4'
  2 => 
    array
      'point' => string '4'

Upvotes: 1

Views: 1037

Answers (3)

Narendrasingh Sisodia
Narendrasingh Sisodia

Reputation: 21437

Simply use as

function checkArray($myArray) {
    $result = array_unique(array_column($myArray, 'point'));
    return (count($result) == 1 && $result[0] == '4') ? "true" : "false";
}
echo checkArray($myArray);

Upvotes: 0

Fabien
Fabien

Reputation: 136

Compare each value in a foreach :

function arrayComparePoint($array) {
$valueCompare = $array[0]['point'];
    foreach ($array as $arrayPoint) {
        foreach ($arrayPoint as $point) {
            if ($valueCompare != $point) {
                return false;
            }
        }
    }
return true;
}

Upvotes: 0

Toumash
Toumash

Reputation: 1087

You just need to use 2 statements fomr PHP. if and for.

I used following script to test it (you can choose one of the loops(for or foreach))

$test = array(array('point' => 4), array('point' => 4));

function checkArrayForPointValue($array, $expectedValue)
{
    $ok = true;
    for ($i = 0; $i < count($array); $i++) {
        if ($array[$i]['point'] != $expectedValue) {
            $ok = false;
            break;
        }
    }
    // choose one of them

    foreach ($array as $element) {
        if ($element['point'] != $expectedValue) {
            $ok = false;
            break;
        }
    }
    return $ok;
}

print(checkArrayForPointValue($test, '4') ? 'yay' : 'not yay');

Upvotes: 1

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