Reputation: 1019
I'm using MVVM and I want to data bind my list of MenuViewModels
to my maim menu. Which consists of a set of menu items and separators.
Here's my MenuItemViewModel code:
public interface IMenuItemViewModel
{
}
[DebuggerDisplay("---")]
public class SeparatorViewModel : IMenuItemViewModel
{
}
[DebuggerDisplay("{Header}, Children={Children.Count}")]
public class MenuItemViewModel : IMenuItemViewModel, INotifyPropertyChanged
{
public event PropertyChangedEventHandler PropertyChanged;
public MenuItemViewModel(string header, ICommand command, ImageSource imageSource)
{
Header = header;
Command = command;
ImageSource = imageSource;
Children = new List<IMenuItemViewModel>();
}
public string Header { get; private set; }
public ICommand Command { get; private set; }
public ImageSource ImageSource { get; private set; }
public IList<IMenuItemViewModel> Children { get; private set; }
}
And my Main window looks like this:
<Window.Resources>
<HierarchicalDataTemplate DataType="{x:Type ViewModel:MenuItemViewModel}"
ItemsSource="{Binding Children}">
<MenuItem Header="{Binding Header}"
Command="{Binding Command}"/>
</HierarchicalDataTemplate>
<DataTemplate DataType="{x:Type ViewModel:SeparatorViewModel}">
<Separator />
</DataTemplate>
</Window.Resources>
<DockPanel>
<Menu DockPanel.Dock="Top"
ItemsSource="{Binding MenuItems}">
</Menu>
</DockPanel>
Should be very simple stuff. Unfortunately, either the menu item looks wrong or the separator is an empty menuItem
(depending on what I've tried).
So, how do I get my Menu
to find my two DataTemplates
?
Upvotes: 11
Views: 5995
Reputation: 5421
Another approach is to:
ControlTemplate
of the MenuItem
so that it uses a Separator
control insteadLike so:
<Menu ItemsSource="{Binding MenuItems}">
<Menu.Resources>
<Style TargetType="{x:Type MenuItem}">
<Setter Property="Header" Value="{Binding Header}" />
<Setter Property="Command" Value="{Binding Command}" />
<Style.Triggers>
<DataTrigger Binding="{Binding IsSeparator}" Value="True">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="{x:Type MenuItem}">
<Separator />
</ControlTemplate>
</Setter.Value>
</Setter>
</DataTrigger>
</Style.Triggers>
</Style>
<HierarchicalDataTemplate DataType="{x:Type ViewModel:MenuItemViewModel}"
ItemsSource="{Binding Children}" />
</Menu.Resources>
</Menu>
Upvotes: 4
Reputation: 1601
A solution without the TemplateSelector:
provide ItemContainerTemplates instead of the DataTemplates :
<ContextMenu ItemsSource="{Binding Path=MenuItems}" UsesItemContainerTemplate="True">
<ContextMenu.Resources>
<ResourceDictionary>
<ItemContainerTemplate DataType="{x:Type ViewModel:MenuItemViewModel }">
<MenuItem Header="{Binding Path=Header}" Command="{Binding Path=Command}" UsesItemContainerTemplate="True">
<MenuItem.Icon>
<Image Source="{Binding Path=ImageSource}"/>
</MenuItem.Icon>
</MenuItem>
</ItemContainerTemplate>
<ItemContainerTemplate DataType="{x:Type ViewModel:SeparatorViewModel}">
<Separator >
<Separator.Style>
<Style TargetType="{x:Type Separator}" BasedOn="{StaticResource ResourceKey={x:Static MenuItem.SeparatorStyleKey}}"/>
</Separator.Style>
</Separator>
</ItemContainerTemplate>
</ResourceDictionary>
</ContextMenu.Resources>
</ContextMenu>
Notes:
Upvotes: 4
Reputation: 1019
Solved my own question
After spending several hours searching the web, I found lots of examples that work against the WPF's natural intentions but none that worked with it.
Here's how to work with the Menu
control and not against it...
A little Background
WPF's Menu
control will normally auto create MenuItem
objects for you when it is binded to a POCO collection, using the ItemsSource
property.
However, this default behavior can be overridden! Here's how...
The Solution
First, you must create a class that derives from ItemContainerTemplateSelector
. Or use the simple class I've created:
public class MenuItemContainerTemplateSelector : ItemContainerTemplateSelector
{
public override DataTemplate SelectTemplate(object item, ItemsControl parentItemsControl)
{
var key = new DataTemplateKey(item.GetType());
return (DataTemplate) parentItemsControl.FindResource(key);
}
}
Second, you must add a reference to the MenuItemContainerTemplateSelector
class to your Windows resources
object, like so:
<Window.Resources>
<Selectors:MenuItemContainerTemplateSelector x:Key="_menuItemContainerTemplateSelector" />
Third, you must set two properties (UsesItemContainerTemplate
, and ItemContainerTemplateSelector
) on both the Menu
and the MenuItem
(which is defined in the HierarchicalDataTemplate
).
Like so:
<HierarchicalDataTemplate DataType="{x:Type ViewModel:MenuItemViewModel}"
ItemsSource="{Binding Children}">
<MenuItem Header="{Binding Header}"
Command="{Binding Command}"
UsesItemContainerTemplate ="true"
ItemContainerTemplateSelector=
"{StaticResource _menuItemContainerTemplateSelector}"/>
</HierarchicalDataTemplate>
<Menu DockPanel.Dock="Top"
ItemsSource="{Binding MenuItems}"
UsesItemContainerTemplate="True"
ItemContainerTemplateSelector=
"{StaticResource _menuItemContainerTemplateSelector}">
</Menu>
Why it Works
For optimization purposes, the Menu
uses the UsesItemContainerTemplate
flag (which has a default value of false
) to skip the DataTemplate
lookup and just returns a normal MenuItem
object. Therefore, we needed to set this value to true
and then our ItemContainerTemplateSelector
works as expected.
Happy Coding!
Upvotes: 22