CODEWITHSUNDEEP
crandom
harlram
harlram

Reputation: 138

How to randomly select 6-letter words from a 26-letter alphabet

I would like to randomly select words (with or without meaning) from 26 letters. The word contains 6 letters, and letter repetitions are allowed.

How can this be done with a program in C (or Objective C)? I would be very grateful for any ideas.

Upvotes: 2

Views: 629

Answers (2)

Matt Joiner
Matt Joiner

Reputation: 118470

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

main()
{
    srand(time(NULL));
    for (int i = 0; i < 6; ++i)
    {
        putchar('a' + (rand() % 26));
    }
    putchar('\n');
    return EXIT_SUCCESS;
}

Salt to taste.

Update0

It would seem the OP does not know how to compile the above. If saved into a file called so.c, compile it with make so CFLAGS=-std=c99 from the same folder.

Upvotes: 5

u0b34a0f6ae
u0b34a0f6ae

Reputation: 49793

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

/* Written by kaizer.se */
void randword(char *buf, size_t len)
{
  char alphabet[] = "abcdefghijklmnopqrstuvxyz";
  size_t i;

  for (i = 0; i < len; i++) {
    size_t idx = ((float)rand()/RAND_MAX) * (sizeof(alphabet) -1);
    buf[i] = alphabet[idx];
  }
  buf[len] = '\0';
}

int main(void) {
  char buf[1024];

  srand(time(NULL));

  randword(buf, 7);
  printf("Word: %s\n", buf);
  return 0;
}

Test:

$ ./rword 
Word: xoilfvv

Upvotes: 0

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