CODEWITHSUNDEEP
iosswiftphone-numberphone-callopenurl
Or Shachar
Or Shachar

Reputation: 59

Swift's openURL method does not place a phone call with an Asterix sign (iOS 8.4)

I'm trying to place a PhoneCall in a swift application. It works pretty simple with regular phone numbers using the openURL method. However, when I try to use a string that contains an asterix (for example, dial the number (****02), the method returns false. I've tried using string literals with no help.

Is it possible to do so at all? Thanks!

    var url:NSURL = NSURL(string: "tel://****02")!
    UIApplication.sharedApplication().openURL(url)

Upvotes: 0

Views: 291

Answers (2)

zrzka
zrzka

Reputation: 21219

Phone Links

... To prevent users from maliciously redirecting phone calls or changing the behavior of a phone or account, the Phone app supports most, but not all, of the special characters in the tel scheme. Specifically, if a URL contains the * or # characters, the Phone app does not attempt to dial the corresponding phone number. ...

Upvotes: 1

Duncan C
Duncan C

Reputation: 131408

I remember reading an answer from somebody that Apple doesn't allow you to dial numbers that contain "*" or "#". If I remember the thread correctly, the rationale was that those let you do things like log in to automated phone systems, and that should be under the user's control.

Upvotes: 0

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