Andy Wong
Andy Wong

Reputation: 351

Better way to remove multiple words from a string?

bannedWord = ["Good", "Bad", "Ugly"]
    
def RemoveBannedWords(toPrint, database):
    statement = toPrint
    for x in range(0, len(database)):
        if bannedWord[x] in statement:
            statement = statement.replace(bannedWord[x] + " ", "")
    return statement
        
toPrint = "Hello Ugly Guy, Good To See You."
    
print(RemoveBannedWords(toPrint, bannedWord))

The output is Hello Guy, To See You. Knowing Python I feel like there is a better way to implement changing several words in a string. I searched up some similar solutions using dictionaries but it didn't seem to fit this situation.

Upvotes: 9

Views: 18654

Answers (5)

Shreevardhan
Shreevardhan

Reputation: 12641

I use

bannedWord = ['Good','Bad','Ugly']
toPrint = 'Hello Ugly Guy, Good To See You.'
print(' '.join(i for i in toPrint.split() if i not in bannedWord))

Upvotes: 16

Ajay Gupta
Ajay Gupta

Reputation: 1285

Here's a solution with regex:

import re
    
def RemoveBannedWords(toPrint,database):
    statement = toPrint
    pattern = re.compile("\\b(Good|Bad|Ugly)\\W", re.I)
    return pattern.sub("", toPrint)
    
toPrint = "Hello Ugly Guy, Good To See You."
    
print(RemoveBannedWords(toPrint,bannedWord))

Upvotes: 13

Subham
Subham

Reputation: 411

As you're checking for the word boundary in the beginning and a non word character at the end, regex is preferable. Still in-memory array/list can also be used

bannedWord = ['Good', 'Bad', 'Ugly']

toPrint = 'Hello Uglyyy Guy, Good To See You.'

for word in bannedWord:
    toPrint = toPrint.replace(word, "")

print(toPrint) 
Hello yy Guy,  To See You.

[Program finished] 

Upvotes: 0

Martin Evans
Martin Evans

Reputation: 46779

Yet another variation on a theme. If you are going to be calling this a lot, then it is best to compile the regex once to improve the speed:

import re

bannedWord = ['Good', 'Bad', 'Ugly']
re_banned_words = re.compile(r"\b(" + "|".join(bannedWord) + ")\\W", re.I)

def RemoveBannedWords(toPrint):
    global re_banned_words
    return re_banned_words.sub("", toPrint)

toPrint = 'Hello Ugly Guy, Good To See You.'
print(RemoveBannedWords(toPrint))

Upvotes: 3

Itachi
Itachi

Reputation: 3005

Slight variation on Ajay's code, when one of the string is a substring of other in the bannedWord list

bannedWord = ['good', 'bad', 'good guy' 'ugly']

The result of toPrint ='good winter good guy' would be

RemoveBannedWords(toPrint,database = bannedWord) = 'winter good'

as it will remove good first. A sorting is required wrt length of elements in the list.

import re

def RemoveBannedWords(toPrint,database):
    statement = toPrint
    database_1 = sorted(list(database), key=len)
    pattern = re.compile(r"\b(" + "|".join(database_1) + ")\\W", re.I)
    return pattern.sub("", toPrint + ' ')[:-1] #added because it skipped last word

toPrint = 'good winter good guy.'

print(RemoveBannedWords(toPrint,bannedWord))

Upvotes: 5

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