How do I get monitor resolution in Python?

Question

What is the simplest way to get monitor resolution (preferably in a tuple)?

Answer 1

If you are using PySimpleGUI you can use:

window.get_screen_size()

This returns a tuple giving the size of the main monitor sreen (even if your window is located on a second monitor screen).

For example:

import PySimpleGUI as sg

layout = [[sg.Button('Print screen size')]]
window = sg.Window('Test', layout)

while True:
    event, values = window.read()
    if event == sg.WINDOW_CLOSED:
        break
    if event == 'Print screen size':
        print(window.get_screen_size())

window.close()

Answer 2

If you're using wxWindows (having installed wxPython), you can simply do:

import wx

app = wx.App(False) # the wx.App object must be created first.    
print(wx.GetDisplaySize())  # returns a tuple

Answer 3

Here is another one which hasn't been mentioned yet. Windows only - uses user32.EnumDisplayMonitors - Pure Python

def get_monitors_resolution():
    user32 = ctypes.windll.user32
    def _get_monitors_resolution():
        monitors = []
        monitor_enum_proc = ctypes.WINFUNCTYPE(
            ctypes.c_int, ctypes.c_ulong, ctypes.c_ulong, ctypes.POINTER(ctypes.wintypes.RECT), ctypes.c_double)
        def callback(hMonitor, hdcMonitor, lprcMonitor, dwData):
            monitors.append((lprcMonitor.contents.right - lprcMonitor.contents.left,
                             lprcMonitor.contents.bottom - lprcMonitor.contents.top))
            return 1
        user32.EnumDisplayMonitors(None, None, monitor_enum_proc(callback), 0)
        return monitors
    resolutions = _get_monitors_resolution()
    allmonitors = {}
    for i, res in enumerate(resolutions):
        allmonitors[i] = {'width': res[0], 'height': res[1]}
    return allmonitors
get_monitors_resolution()
Out[2]: {0: {'width': 1920, 'height': 1080}, 1: {'width': 1920, 'height': 1080}}

Answer 4

I created a PyPI module for this reason:

pip install screeninfo

The code:

from screeninfo import get_monitors
for m in get_monitors():
    print(str(m))

Result:

Monitor(x=3840, y=0, width=3840, height=2160, width_mm=1420, height_mm=800, name='HDMI-0', is_primary=False)
Monitor(x=0, y=0, width=3840, height=2160, width_mm=708, height_mm=399, name='DP-0', is_primary=True)

It supports multi monitor environments. Its goal is to be cross platform; for now it supports Cygwin and X11 but pull requests are totally welcome.

Answer 5

Late to the game. I think I found the cross-platform using the dependence-free library mss that supports multiple monitors (https://pypi.org/project/mss/):

import mss
sct=mss.mss()
sct.monitors

Then you get something like this:

[{'left': -1440, 'top': 0, 'width': 4000, 'height': 1080},
 {'left': 0, 'top': 0, 'width': 2560, 'height': 1080},
 {'left': -1440, 'top': 180, 'width': 1440, 'height': 900}]

The element 0 is the virtual screen combining all monitors. The element 1 is the primary monitor, and element 2 the second monitor.

Answer 6

Try using pyautogui.size()!

import pyautogui #pip install pyautogui

x = pyautogui.size()[0] # getting the width of the screen
y = pyautogui.size()[1] # getting the height of the screen

print(x,y) 

Answer 7

A cross-platform and easy way to do this is by using Tkinter that comes with nearly all the Python versions, so you don't have to install anything:

import tkinter
root = tkinter.Tk()
root.withdraw()
WIDTH, HEIGHT = root.winfo_screenwidth(), root.winfo_screenheight()

Answer 8

Using Linux, the simplest way is to execute Bash command

xrandr | grep '*'

And parse its output using a regular expression.

Also you can do it through Pygame: Pygame - Get screen size

Answer 9

Using Linux

Instead of a regular expression, take the first line and take out the current resolution values.

Current resolution of display :0

>>> screen = os.popen("xrandr -q -d :0").readlines()[0]
>>> print screen
Screen 0: minimum 320 x 200, current 1920 x 1080, maximum 1920 x 1920
>>> width = screen.split()[7]
>>> print width
1920
>>> height = screen.split()[9][:-1]
>>> print height
1080
>>> print "Current resolution is %s x %s" % (width,height)
Current resolution is 1920 x 1080

This was done on xrandr 1.3.5, I don't know if the output is different on other versions, but this should make it easy to figure out.

Answer 10

X Window version:

#!/usr/bin/python

import Xlib
import Xlib.display

resolution = Xlib.display.Display().screen().root.get_geometry()
print str(resolution.width) + "x" + str(resolution.height)

Answer 11

Taken directly from an answer to the post How can I get the screen size in Tkinter?,

import tkinter as tk

root = tk.Tk()

screen_width = root.winfo_screenwidth()
screen_height = root.winfo_screenheight()

Answer 12

If you are using the Qt toolkit, specifically PySide, you can do the following:

from PySide import QtGui
import sys

app = QtGui.QApplication(sys.argv)
screen_rect = app.desktop().screenGeometry()
width, height = screen_rect.width(), screen_rect.height()

Answer 13

On Windows 8.1 I am not getting the correct resolution from either ctypes or tk. Other people are having this same problem for ctypes: getsystemmetrics returns wrong screen size

To get the correct full resolution of a high DPI monitor on Windows 8.1, one must call SetProcessDPIAware and use the following code:

import ctypes
user32 = ctypes.windll.user32
user32.SetProcessDPIAware()
[w, h] = [user32.GetSystemMetrics(0), user32.GetSystemMetrics(1)]

Full Details Below:

I found out that this is because windows is reporting a scaled resolution. It appears that python is by default a 'system dpi aware' application. Types of DPI aware applications are listed here: High DPI Desktop Application Development on Windows

Basically, rather than displaying content the full monitor resolution, which would make fonts tiny, the content is scaled up until the fonts are big enough.

On my monitor I get:
Physical resolution: 2560 x 1440 (220 DPI)
Reported python resolution: 1555 x 875 (158 DPI)

Per this Windows site: Adjusting Scale for Higher DPI Screens. The formula for reported system effective resolution is:

(reported_px*current_dpi)/(96 dpi) = physical_px

I'm able to get the correct full screen resolution, and current DPI with the below code. Note that I call SetProcessDPIAware() to allow the program to see the real resolution.

import tkinter as tk
root = tk.Tk()

width_px = root.winfo_screenwidth()
height_px = root.winfo_screenheight()
width_mm = root.winfo_screenmmwidth()
height_mm = root.winfo_screenmmheight()
# 2.54 cm = in
width_in = width_mm / 25.4
height_in = height_mm / 25.4
width_dpi = width_px/width_in
height_dpi = height_px/height_in

print('Width: %i px, Height: %i px' % (width_px, height_px))
print('Width: %i mm, Height: %i mm' % (width_mm, height_mm))
print('Width: %f in, Height: %f in' % (width_in, height_in))
print('Width: %f dpi, Height: %f dpi' % (width_dpi, height_dpi))

import ctypes
user32 = ctypes.windll.user32
user32.SetProcessDPIAware()
[w, h] = [user32.GetSystemMetrics(0), user32.GetSystemMetrics(1)]
print('Size is %f %f' % (w, h))

curr_dpi = w*96/width_px
print('Current DPI is %f' % (curr_dpi))

Which returned:

Width: 1555 px, Height: 875 px
Width: 411 mm, Height: 232 mm
Width: 16.181102 in, Height: 9.133858 in
Width: 96.099757 dpi, Height: 95.797414 dpi
Size is 2560.000000 1440.000000
Current DPI is 158.045016

I am running Windows 8.1 with a 220 DPI capable monitor. My display scaling sets my current DPI to 158.

I'll use the 158 to make sure my Matplotlib plots are the right size with:

from pylab import rcParams
rcParams['figure.dpi'] = curr_dpi

Answer 14

If you are working on Windows OS, you can use OS module to get it:

import os
cmd = 'wmic desktopmonitor get screenheight, screenwidth'
size_tuple = tuple(map(int,os.popen(cmd).read().split()[-2::]))

It will return a tuple (Y,X) where Y is the vertical size and X is the horizontal size. This code works on Python 2 and Python 3

UPDATE

For Windows 8/8.1/10, the above answer doesn't work, use the next one instead:

import os
cmd = "wmic path Win32_VideoController get CurrentVerticalResolution,CurrentHorizontalResolution"
size_tuple = tuple(map(int,os.popen(cmd).read().split()[-2::]))

Answer 15

On Linux:

import subprocess
import re

def getScreenDimensions():
    xrandrOutput = str(subprocess.Popen(['xrandr'], stdout=subprocess.PIPE).communicate()[0])
    matchObj = re.findall(r'current\s(\d+) x (\d+)', xrandrOutput)
    if matchObj:
        return (int(matchObj[0][0]), int(matchObj[0][1]))

screenWidth, screenHeight = getScreenDimensions()
print(f'{screenWidth} x {screenHeight}')

Answer 16

A lot of these answers use tkinter to find the screen height/width (resolution), but sometimes it is necessary to know the dpi of your screen cross-platform compatible. This answer is from this link and left as a comment on another post, but it took hours of searching to find. I have not had any issues with it yet, but please let me know if it does not work on your system!

import tkinter
root = tkinter.Tk()
dpi = root.winfo_fpixels('1i')

The documentation for this says:

winfo_fpixels(number)
# Return the number of pixels for the given distance NUMBER (e.g. "3c") as float

A distance number is a digit followed by a unit, so 3c means 3 centimeters, and the function gives the number of pixels on 3 centimeters of the screen (as found here). So to get dpi, we ask the function for the number of pixels in 1 inch of screen ("1i").

Answer 17

Utility script using pynput library. Posting here for ref.:

 
from pynput.mouse import Controller as MouseController

def get_screen_size():
    """Utility function to get screen resolution"""

    mouse = MouseController()

    width = height = 0

    def _reset_mouse_position():
        # Move the mouse to the top left of 
        # the screen
        mouse.position = (0, 0)

    # Reset mouse position
    _reset_mouse_position()

    count = 0
    while 1:
        count += 1
        mouse.move(count, 0)
        
        # Get the current position of the mouse
        left = mouse.position[0]

        # If the left doesn't change anymore, then
        # that's the screen resolution's width
        if width == left:
            # Add the last pixel
            width += 1

            # Reset count for use for height
            count = 0
            break

        # On each iteration, assign the left to 
        # the width
        width = left
    
    # Reset mouse position
    _reset_mouse_position()

    while 1:
        count += 1
        mouse.move(0, count)

        # Get the current position of the mouse
        right = mouse.position[1]

        # If the right doesn't change anymore, then
        # that's the screen resolution's height
        if height == right:
            # Add the last pixel
            height += 1
            break

        # On each iteration, assign the right to 
        # the height
        height = right

    return width, height

---

>>> get_screen_size()
(1920, 1080)

Answer 18

For Linux, you can use this:

import gi
gi.require_version("Gdk", "3.0")
from gi.repository import Gdk

s = Gdk.Screen.get_default()
screen_width = s.get_width()
screen_height = s.get_height()
print(screen_width)
print(screen_height)

Answer 19

For later versions of PyGtk:

import gi
gi.require_version("Gdk", "3.0")
from gi.repository import Gdk

display = Gdk.Display.get_default()
n_monitors = display.get_n_monitors()
print("there are %d monitors" % n_monitors)
for m in range(n_monitors):
  monitor = display.get_monitor(m)
  geometry = monitor.get_geometry()
  print("monitor %d: %d x %d" % (m, geometry.width, geometry.height))

Answer 20

Expanding on @user2366975's answer, to get the current screen size in a multi-screen setup using Tkinter (code in Python 2/3):

try:
    # for Python 3
    import tkinter as tk
except ImportError:
    # for Python 2
    import Tkinter as tk


def get_curr_screen_geometry():
    """
    Workaround to get the size of the current screen in a multi-screen setup.

    Returns:
        geometry (str): The standard Tk geometry string.
            [width]x[height]+[left]+[top]
    """
    root = tk.Tk()
    root.update_idletasks()
    root.attributes('-fullscreen', True)
    root.state('iconic')
    geometry = root.winfo_geometry()
    root.destroy()
    return geometry

(Should work cross-platform, tested on Linux only)

Answer 21

It's a little troublesome for retina screen, i use tkinter to get the fake size, use pilllow grab to get real size :

import tkinter
root = tkinter.Tk()
resolution_width = root.winfo_screenwidth()
resolution_height = root.winfo_screenheight()
image = ImageGrab.grab()
real_width, real_height = image.width, image.height
ratio_width = real_width / resolution_width
ratio_height = real_height/ resolution_height

Answer 22

Old question but this is missing. I'm new to python so please tell me if this is a "bad" solution. This solution is supported for Windows and MacOS only and it works just for the main screen - but the os is not mentioned in the question.

Measure the size by taking a screenshot. As the screensize should not change this has to be done only once. There are more elegant solutions if you have a gui toolkit like GTK, wx, ... installed.

see Pillow

pip install Pillow

---

from PIL import ImageGrab

img = ImageGrab.grab()
print (img.size)

Answer 23

On Linux we can use subprocess module

import subprocess
cmd = ['xrandr']
cmd2 = ['grep', '*']
p = subprocess.Popen(cmd, stdout=subprocess.PIPE)
p2 = subprocess.Popen(cmd2, stdin=p.stdout, stdout=subprocess.PIPE)
p.stdout.close()

resolution_string, junk = p2.communicate()
resolution = resolution_string.split()[0]
resolution = resolution.decode("utf-8") 
width = int(resolution.split("x")[0].strip())
heigth = int(resolution.split("x")[1].strip())

Answer 24

In Windows, you can also use ctypes with GetSystemMetrics():

import ctypes
user32 = ctypes.windll.user32
screensize = user32.GetSystemMetrics(0), user32.GetSystemMetrics(1)

so that you don't need to install the pywin32 package; it doesn't need anything that doesn't come with Python itself.

For multi-monitor setups, you can retrieve the combined width and height of the virtual monitor:

import ctypes
user32 = ctypes.windll.user32
screensize = user32.GetSystemMetrics(78), user32.GetSystemMetrics(79)

Answer 25

On Windows:

from win32api import GetSystemMetrics

print("Width =", GetSystemMetrics(0))
print("Height =", GetSystemMetrics(1))

If you are working with high resolution screen, make sure your python interpreter is HIGHDPIAWARE.

Based on this post.

Answer 26

You could use PyMouse. To get the screen size just use the screen_size() attribute:

from pymouse import PyMouse
m = PyMouse()
a = m.screen_size()

a will return a tuple, (X, Y), where X is the horizontal position and Y is the vertical position.

Link to function in documentation.

Answer 27

In case you have PyQt4 installed, try the following code:

from PyQt4 import QtGui
import sys

MyApp = QtGui.QApplication(sys.argv)
V = MyApp.desktop().screenGeometry()
h = V.height()
w = V.width()
print("The screen resolution (width X height) is the following:")
print(str(w) + "X" + str(h))

For PyQt5, the following will work:

from PyQt5 import QtWidgets
import sys

MyApp = QtWidgets.QApplication(sys.argv)
V = MyApp.desktop().screenGeometry()
h = V.height()
w = V.width()
print("The screen resolution (width X height) is the following:")
print(str(w) + "X" + str(h))

Answer 28

Using pygame:

import pygame
pygame.init()
infos = pygame.display.Info()
screen_size = (infos.current_w, infos.current_h)

[1]

However, if you're trying to set your window to the size of the screen, you might just want to do:

pygame.display.set_mode((0,0),pygame.FULLSCREEN)

to set your display to fullscreen mode. [2]

Answer 29

Another version using xrandr:

import re
from subprocess import run, PIPE

output = run(['xrandr'], stdout=PIPE).stdout.decode()
result = re.search(r'current (\d+) x (\d+)', output)
width, height = map(int, result.groups()) if result else (800, 600)

Answer 30

Try pyautogui:

import pyautogui
resolution = pyautogui.size()
print(resolution)