CODEWITHSUNDEEP
c#arraysparsingsplit
Colonder
Colonder

Reputation: 1576

How to split a long entered in TextBox control into int array

I just started to learn C# and already have a question, maybe quite dumb.

I'm writing a little desktop program (Windows Forms) that checks whether entered bank account number is valid or computes missing control numbers. To check number validity we must multiply each digit in that number by corresponding factor. My problem is:

When I enter whole number (26 digits) in TextBlock control and click Check button I need to parse that number into int array somehow. I saw some examples already and tried

int[] array = new int[26];
char[] sep = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'};

String[] numbers = inputWindow.Text.Split(sep);

for (int i = 0; i < 26; i++)
    array[i] = Int32.Parse(numbers[i]);

But got FormatException. I also tried 

array = inputWindow.Text.Split().Select(h => Int32.Parse(h)).ToArray());

Or something similar but got OverflowException. Int64.Parse resulted in obvious type conversion error. How to accomplish that parsing?

Thanks in advance

EDIT My bad, there was 30 instead of 26, but that actually didn't matter.

Upvotes: 3

Views: 1597

Answers (4)

abhi8569
abhi8569

Reputation: 131

This code snippet can be used to convert TextBox text to integer array. But you have to make sure that user will input only interger in textBox.

  int[] array = new int[30];
        char[] sample = textBox1.Text.ToCharArray();

        for (int i = 0; i < 26; i++)
            array[i] = int.Parse(sample[i].ToString());

Upvotes: 0

Grant Winney
Grant Winney

Reputation: 66449

That second snippet is almost there (assuming you want an array of numbers, and that the Text property has only numbers in it).

Remove the call to Split(), and the Select() portion will iterate over each character in the string.

var array = inputWindow.Text.Select(i => Convert.ToInt32(i-48)).ToArray();

Upvotes: 3

Brian Flaherty
Brian Flaherty

Reputation: 39

I just did this in a console application and I was able to get the numbers into the array. I did no math on each one. I assume you could take it from there. I also recommend using a List instead of an array so the size is not fixed.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
  class Program
  {
    static void Main(string[] args)
    {
        Console.Write("Number: ");
        string inputStr = Console.ReadLine();
        int[] array = new int[30];

        int i = 0;
        foreach(Char c in inputStr)
        {
            array[i] = Convert.ToInt32(c.ToString());
            i++;
        }

        Console.WriteLine("");

        foreach (int num in array)
        {
            Console.WriteLine(num.ToString());
        }

        Console.ReadLine();
    }
  }
}

Upvotes: 1

Sky Fang
Sky Fang

Reputation: 1101

Your whole number just 26 digits,but your i set max is 30 for (int i = 0; i < 30; i++), 26 is less than 30,so array[i] = Int32.Parse(numbers[i]) throw OverflowException

Upvotes: 0

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