CODEWITHSUNDEEP
phpmysqlrandomxamppshuffle
TARA
TARA

Reputation: 527

How to Display Sequence Random Data like the result before on MySQL using PHP?

Hello i have tables like this :

Employee

EmployeeID  EmployeeName 
1234        Nayeon     
1235        Jihyo     
1236        Jungyeon     
1237        Dahyun     
1238        Sana       
1239        Mina
1240        Tzuyu
1241        Chaeyeong
1241        Chaeyeong
1242        Momo

i used this source code :

<?php

mysql_connect("localhost", "root", "1234") or die(mysql_error());
mysql_select_db("Employee") or die(mysql_error());

$employees = mysql_query("SELECT * FROM Employee ORDER BY EmployeeID") 
or die(mysql_error());  

$letters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
$position = 0;
$position2 = 0;
$toomany = '';

while($row = mysql_fetch_array( $employees )) {
    echo "<DIV>" . $toomany.substr($letters, $position, 1) . " = " . $row['EmployeeName'] . " </div>";
      $position ++;
    if($position > 25) {
        $position = 0;
        $position2 ++;
        if($position2 > 25) { echo "We need to rethink this idea."; break; }
        $toomany = substr($letters, $position2, 1);
    }
}
?>

to display these data :

 A  = Nayeon     
 B  = Jihyo     
 C  = Jungyeon     
 D  = Dahyun     
 E  = Sana       
 F  = Mina
 G  = Tzuyu
 F  = Chaeyeong
 H  = Chaeyeong
 I  = Momo

The problem is i want to random that data like this (from the result before):

C  = Jungyeon 
A  = Nayeon 
H  = Chaeyeong    
B  = Jihyo 
I  = Momo        
F  = Mina
G  = Tzuyu
E  = Sana  
F  = Chaeyeong
D  = Dahyun

so i add codes like this :

 <?php

mysql_connect("localhost", "root", "1234") or die(mysql_error());
mysql_select_db("Employee") or die(mysql_error());

$employees = mysql_query("SELECT * FROM Employee ORDER BY EmployeeID") 
or die(mysql_error());  

$letters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
$position = 0;
$position2 = 0;
$toomany = '';

while($row = mysql_fetch_array( $employees )) {
    echo "<DIV>" . $toomany.substr($letters, $position, 1) . " = " . $row['EmployeeID'] . " </div>";
      $position ++;
    if($position > 25) {
        $position = 0;
        $position2 ++;
        if($position2 > 25) { echo "We need to rethink this idea."; break; }
        $toomany = substr($letters, $position2, 1);
    }
}


function generateRandomString($length = 10) {
    $characters = $positions;
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
        $randomString .= $characters[rand(0, $charactersLength - 1)];
    }
    return $randomString;
}


echo generateRandomString();

?>

but does not work, may you know where is the problem? Thank you

Upvotes: 0

Views: 82

Answers (1)

Kansuler
Kansuler

Reputation: 1579

You could use Shuffle to randomize the array you get from mysql_fetch_array.

It would look something like this:

$letters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';

$array = array();

while($row = mysql_fetch_assoc($employees)){
    $array[] = $row
}

$i = 0;

// Assign a letter to each employee in the correct order
foreach($array as $Key => $row){
    $array[$Key]["letter"] = substr($letters, $i, 1);
    $i++;
    if($i > 25){
        $i = 0;
    }
}

// Shuffle the array
shuffle($array);

// Print each entry with correctly assigned letter and name.
foreach($array as $row) {
    echo "<DIV>" . $row["letter"] . " = " . $row['EmployeeName'] . " </div>";
}

Upvotes: 1

Related Questions