CODEWITHSUNDEEP
c#regex
Sandeep
Sandeep

Reputation: 1210

c# Regex to match end of string?

I need help to generate regex so that it will match any string which has following detail correct:

  1. String should end with bracket and only numbers inside it.
  2. End bracket should appear only once at the end of line and not any where else.
  3. Any characters are allowed before bracket start
  4. No characters are allowed after bracket end
  5. String should contain only 1 set of brackets with numbers, i.e. no double brackets like (( or ))

I have tried this .\([0-9]+\)$ but this is not what i required.

For example:

Following string should match:

asds-xyz (1)
asds+-xyz (12)
as@ds-xyz (123)

Following strings should not be matched:

asds-xyz ((1)
asds-xyz ((12sdf))
(123) asds-xyz
xyz ((2)
XYX (1))
XYZ (1)(2)
xyz(1)BXZ
xyz(1)BXZ(2)

Upvotes: 2

Views: 18082

Answers (3)

Sebastian Schumann
Sebastian Schumann

Reputation: 3446

^[^\(\)]*\(\d+\)$

will do the job...

\d = [0-9]

Upvotes: 2

Liem Do
Liem Do

Reputation: 943

Starting from your regex: .\([0-9]+\)$ . match everything but you need quantifier for this. So add * to this .*\([0-9]+\)$ But the problem is, it will match ( and ) before the last bracket like xyz ((2) So make a negative set for this, the final result:

^(.*[^\(\)])(\([0-9]+\))$

Upvotes: -1

n00b
n00b

Reputation: 1852

I try to fix with minimum change to your pattern: you have to use the [^ key to exclude brackets before your only desired bracket. like this

[^\(\)]*\([0-9]+\)$

That would find the patterns you like, and if you like the whole string to be like that, then simply add a ^ in the beginning

Upvotes: 1

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