CODEWITHSUNDEEP
javaregexsplitdelimiter
Sean
Sean

Reputation: 1313

Java string split with multiple delimeters

What would be the best way to split this string directly after the CN= to store both the first and last name in separate fields as shown below?

String distinguisedName = "CN=Paul M. Sebula,OU=BBB,OU=Users,OU=TIES Project,DC=SPHQTest,DC=na,DC=BBBBBB,DC=com"
String firstName"Paul"
String lastName="Sebula"

Upvotes: 1

Views: 198

Answers (5)

Jacob Zwiers
Jacob Zwiers

Reputation: 1102

Don't re-invent the wheel. Assuming these are well-formed DN's, see the accepted answer on this question for how to parse without directly writing your own regex: Parsing the CN out of a certificate DN

Once you've extracted the CN, then you can apply some of the other parsing techniques suggested (use the Java StringTokenizer or the String.split() method as others here have suggested if it's known to be separated only by spaces). That assumes that you can make assumptions (eg. the first element in the resulting array is the firstName,the last element is the lastName and everything in between is middle names / initials) about the CN format.

Upvotes: 3

KDP
KDP

Reputation: 1481

public static void main(String[] args) {

    String distinguisedName = "CN=Paul M. Sebula,OU=BBB,OU=Users,OU=TIES Project,DC=SPHQTest,DC=na,DC=BBBBBB,DC=com";
    String splitResult[]=distinguisedName.split(",")[0].split("=");
    String resultTwo[]=splitResult[1].split("\\.");
    String firstName=resultTwo[0].split(" ")[0].trim();
    String lastName=resultTwo[1].trim();
    System.out.println(firstName);
    System.out.println(lastName);

}

output

Paul

Sebula

Upvotes: 1

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 627507

You can use split:

String distinguisedName = "CN=Paul Sebula,OU=BAE,OU=Users,OU=TIES Project,DC=SPHQTest,DC=na,DC=baesystems,DC=com";
String[] names = distinguisedName.split(",")[0].split("=")[1].split(" ");
String firstName = names[0]; 
String lastName= names.length > 2 ? names[names.length-1] : names[1];
System.out.println(firstName + " " + lastName);

See IDEONE demo, output: Paul Sebula.

This also accounts for just 2 names (first and last only). Note how last name is accessed it being the last item in the array.

Upvotes: 1

GriffeyDog
GriffeyDog

Reputation: 8386

In steps:

String distinguisedName = "CN=Paul M. Sebula,OU=BBB,OU=Users,OU=TIES Project,DC=SPHQTest,DC=na,DC=BBBBBB,DC=com";
String fullName = distinguisedName.substring(3, distinguisedName.indexOf(','));
String[] nameParts = fullName.split(" ");
String firstName = nameParts[0];
String lastName = nameParts[nameParts.length-1];

This will work for cases where the middle name/initial are not present as well.

Upvotes: 0

dbillz
dbillz

Reputation: 210

String distinguisedName = "CN=Paul M. Sebula,OU=BBB,OU=Users,OU=TIES Project,DC=SPHQTest,DC=na,DC=BBBBBB,DC=com"

String[] commaSplit = distinguisedName.split(',');
String[] whitespaceSplit = commaSplit[0].split(' ');
String firstName = whitespaceSplit[0].substring(3);
String lastName = whiteSpaceSplit[2];

Upvotes: 0

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