CODEWITHSUNDEEP
phpregex
Jean-philippe Emond
Jean-philippe Emond

Reputation: 1614

php: preg_match failed with special character pattern

I have an issue with php regex. I have same regex in JS and it works. I don't know what is the problem.

this is the php code regex:

echo $password; // 9Gq!Q23Lne;<||.'/\
$reg_password = "/^[-_0-9a-záàâäãåçéèêëíìîïñóòôöõúùûüýÿæœÁÀÂÄÃÅÇÉÈÊËÍÌÎÏÑÓÒÔÖÕÚÙÛÜÝŸÆŒ0\d!@#$%^&*()_\+\{\}:\"<>?\|\[\];\',\.\/\x5c~]{6,30}$/i";
if(isset($password) &&
  (!preg_match($reg_password, $password) || !preg_match("#[a-z]#", $password) || !preg_match("#[\d]#", $password))
){
   echo "you failed";
 }

original password from html input: 

9Gq!Q23Lne;<||.\'/\

it is the same value just before the $reg_password.

I have make a test using escape_string from mysqli method but it doesn't work too:

$password = $this->db->escape_string($password);
echo $password; // 9Gq!Q23Lne;<||.\'/\\

I don't know what is my problem because I have used regex101.com to test it and it works..

Any idea about that? Thanks

Upvotes: 3

Views: 262

Answers (2)

Ali
Ali

Reputation: 3081

In your pattern, you need to use single quote instead of double ;)

So it will be like this 

$reg_password = '/^[-_0-9a-záàâäãåçéèêëíìîïñóòôöõúùûüýÿæœÁÀÂÄÃÅÇÉÈÊËÍÌÎÏÑÓÒÔÖÕÚÙÛÜÝŸÆŒ0\d!@#$%^&*()_\+\{\}:\"<>?\|\[\];\',\.\/\x5c~]{6,30}$/i';

Upvotes: 2

anubhava
anubhava

Reputation: 786291

You don't need to call preg_match multiple times, just use lookahead to enforce your rules as in this regex:

^(?=.*?\d)(?=.*?[a-z])[-\wáàâäãåçéèêëíìîïñóòôöõúùûüýÿæœÁÀÂÄÃÅÇÉÈÊËÍÌÎÏÑÓÒÔÖÕÚÙÛÜÝŸÆŒ0\d!@#$%^&*()+{}:"<>?|\[\];',./\x5c~]{6,30}$

RegEx Demo

Code:

$re = "`^(?=.*?\\d)(?=.*?[a-z])[-\\wáàâäãåçéèêëíìîïñóòôöõúùûüýÿæœÁÀÂÄÃÅÇÉÈÊËÍÌÎÏÑÓÒÔÖÕÚÙÛÜÝŸÆŒ0\\d!@#$%^&*()+{}:\"<>?|\\[\\];',./\\x5c~]{6,30}$`mu";
$str = "9Gq!Q23Lne;<||.\'/\\"; 

if (!preg_match($re, $input)) {
   echo "you failed";
}

Upvotes: 0

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