CODEWITHSUNDEEP
python
Zhanna D.
Zhanna D.

Reputation: 31

Loops and Strings in python

Given the strings s1 and s2, not necessarily of the same length. Create a new string consisting of alternating characters of s1 and s2 (that is, the first character of s1 followed by the first character of s2, followed by the second character of s1, followed by the second character of s2, and so on.

Once the end of either string is reached, the remainder of the longer string is added to the end of the new string. For example, if s1 contained "abc" and s2 contained "uvwxyz", then the new string should contain "aubvcwxyz". Associate the new string with the variable s3.

My attempt is:

s3 = '' 
i = 0 
while i < len(s1) and i < len(s2): 
    s3 += s1[i] + s2[i] 
    i += 1 
    if len(s1) > len(s2): 
        s3 += s1[i:] 
    elif len(s2) > len(s1): 
        s3 += s2[i:]

Upvotes: 2

Views: 12473

Answers (6)

huan wang
huan wang

Reputation: 1

i = 0
s3 = ''
minLen = min(len(s1),len(s2))
while i < minLen:
    s3 = s3+ s1[i] + s2[i]
    i += 1
if maxLen != minLen:
    s3 += s1[minLen:]+s2[minLen:]

Upvotes: -1

Mustafa Kurt
Mustafa Kurt

Reputation: 1

we can first decide which string is longer then write a for loop for that condition. 

s3 = ""
i=0
if len(s1)>len(s2):
    for i in range(len(s2)) :
        s3 = s3 + s1[i] + s2[i]
        i=i+1
    s3=s3+s1[i:]
else:
    for i in range(len(s1)) :
        s3 = s3 + s1[i] + s2[i]
        i=i+1
    s3=s3+s2[i:]

Upvotes: 0

Orkun Berk Yuzbasioglu
Orkun Berk Yuzbasioglu

Reputation: 165

In python3.x, the following code block works, because Python slices return all of elements in range or an empty string if the index values aren't valid for that string:

n = min(len(s1),len(s2))
s3=""

for i in range(0,n):
    s3 = s3 + s1[i] + s2[i]

s3 = s3 + s1[n:] + s2[n:]

Upvotes: 0

A K
A K

Reputation: 1674

a = 'abc'
b= 'uxyz'
c=''
t=0

while t<len(a):
    c+=a[t]+b[t]
    t+=1

c+=b[t:]
print(c)

This should be the bare minimum for you to tweak some more so you learn from this. I suggest adding some conditionals and turning it into a function so it can take so s1 and s2 can be any length and it will still work. That'll be fun~

Upvotes: 0

Iron Fist
Iron Fist

Reputation: 10951

You can do it using izip_longest method from itertools module, this way:

import itertools as it
s3 = ''.join(''.join(item) for item in it.izip_longest(s1,s2,fillvalue=''))

DEMONSTRATION:

>>> s1 = 'ABCDEF'
>>> s2 = '123456789'
>>> s3 = ''.join(''.join(item) for item in it.izip_longest(s1,s2,fillvalue=''))
>>> 
>>> s3
'A1B2C3D4E5F6789'

EDIT: in avoiding multiple join:

s3 = ''.join(c for item in it.izip_longest(s1,s2,fillvalue='') for c in item)

Upvotes: 1

altblahblah
altblahblah

Reputation: 51

s1 = "abcdefg"
s2 = "hijk"
s3 = ""
minLen = min(len(s1), len(s2))
    for x in range(minLen):
    out += s1[x]
    out += s2[x]
out += s1[minLen:]
print out

A couple of things to keep in mind. First, you can treat a python string like an array, and you can access the item at given index using brackets. Also, the second to last line makes use of splicing, for more information, see How can I splice a string?

Upvotes: 3

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