CODEWITHSUNDEEP
scalastring-interpolation
user4063815
user4063815

Reputation:

String interpolation, escaping quotation mark

I'm somewhat baffled by how difficult this turns out to be. I've already looked around stackoverflow, but no solution seems to work fine for me.

What I want to do:

val file = checkcache(fileName)

file match
{
    case Some(_) => {println(s"File $file found!"); file.get}
    case None => createFile(fileName)
}

Now, this works perfectly fine, for a file named "blubb" that already resides in the cache it outprints

File blubb found

and returns the file.

Now I want this to be

File "blubb" found

So I tried doing this:

case Some(_) => { println(s"File \" $file \" found!"); file.get}

Compiler throws

')' expected but string literal found.

Why is that and how do I escape a double quotation mark correctly and preferably without an empty space after or before the $file-variable?

Upvotes: 6

Views: 3768

Answers (1)

Nikita
Nikita

Reputation: 4515

Use triple quotation mark:

scala> s"""File "$file" found!"""
res0: String = File "blubb" found!

Upvotes: 16

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