CODEWITHSUNDEEP
iosswift
Justin
Justin

Reputation: 11

int32 is not convertible to int

I'm trying to make a random number generator ios app in xcode and I'm getting an error while trying to use the rand() method I get the following error; "int32 is not convertible to int" I've tried to change "int" to "int32" and it gave me no errors but since I did that no numbers are displayed. How do I get around this problem?

Note: I'm using swift language

Code:

@IBOutlet var lblNum: UILabel!
@IBAction func btnGenerateNum(sender: UIButton, forEvent event: UIEvent) {
    let text: Int = rand()

    switch(text) {
    case 0:
    lblNum.text = "0"
    break;

    case 1:
        lblNum.text = "1"
        break;

    case 2:
        lblNum.text = "2"
        break;

    case 3:
        lblNum.text = "3"
        break;

    case 4:
        lblNum.text = "4"
        break;

    case 5:
        lblNum.text = "5"
        break;

    case 6:
        lblNum.text = "6"
        break;

    case 7:
        lblNum.text = "7"
        break;

    case 8:
        lblNum.text = "8"
        break;

    case 9:
        lblNum.text = "9"
        break;

    default:
        break;
    }

Upvotes: 0

Views: 231

Answers (3)

Syed Tariq
Syed Tariq

Reputation: 2938

Would this be easier for you? (Not necessarily a solution to the random number generator issue that you raised)

let text = String((Int(rand())) % 10)
lblNum.text = text

Upvotes: 0

Leo Dabus
Leo Dabus

Reputation: 236568

@IBAction func btnGenerateNum(sender: UIButton, forEvent event: UIEvent) {

    lblNum.text = "\(arc4random_uniform(10))"
}

Upvotes: 1

Lyndsey Scott
Lyndsey Scott

Reputation: 37300

Simply initialize an Int with your Int32:

let text: Int = Int(rand())

Upvotes: 1

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