Reputation: 11302
What is the slickest way to programatically read from stdin or an input file (if provided) in Perl?
Upvotes: 84
Views: 172538
Reputation: 19236
You need to use <> operator:
while (<>) {
print $_; # or simply "print;"
}
Which can be compacted to:
print while (<>);
Arbitrary file:
open my $F, "<file.txt" or die $!;
while (<$F>) {
print $_;
}
close $F;
Upvotes: 18
Reputation: 683
This provides a named variable to work with:
foreach my $line ( <STDIN> ) {
chomp( $line );
print "$line\n";
}
To read a file, pipe it in like this:
program.pl < inputfile
Upvotes: 55
Reputation: 46985
while (<>) {
print;
}
will read either from a file specified on the command line or from stdin if no file is given
If you are required this loop construction in command line, then you may use -n
option:
$ perl -ne 'print;'
Here you just put code between {}
from first example into ''
in second
Upvotes: 102
Reputation: 169
Here is how I made a script that could take either command line inputs or have a text file redirected.
if ($#ARGV < 1) {
@ARGV = ();
@ARGV = <>;
chomp(@ARGV);
}
This will reassign the contents of the file to @ARGV, from there you just process @ARGV as if someone was including command line options.
WARNING
If no file is redirected, the program will sit their idle because it is waiting for input from STDIN.
I have not figured out a way to detect if a file is being redirected in yet to eliminate the STDIN issue.
Upvotes: -1
Reputation: 119
If there is a reason you can't use the simple solution provided by ennuikiller above, then you will have to use Typeglobs to manipulate file handles. This is way more work. This example copies from the file in $ARGV[0]
to that in $ARGV[1]
. It defaults to STDIN
and STDOUT
respectively if files are not specified.
use English;
my $in;
my $out;
if ($#ARGV >= 0){
unless (open($in, "<", $ARGV[0])){
die "could not open $ARGV[0] for reading.";
}
}
else {
$in = *STDIN;
}
if ($#ARGV >= 1){
unless (open($out, ">", $ARGV[1])){
die "could not open $ARGV[1] for writing.";
}
}
else {
$out = *STDOUT;
}
while ($_ = <$in>){
$out->print($_);
}
Upvotes: 11
Reputation: 823
The "slickest" way in certain situations is to take advantage of the -n
switch. It implicitly wraps your code with a while(<>)
loop and handles the input flexibly.
In slickestWay.pl
:
#!/usr/bin/perl -n BEGIN: { # do something once here } # implement logic for a single line of input print $result;
At the command line:
chmod +x slickestWay.pl
Now, depending on your input do one of the following:
Wait for user input
./slickestWay.pl
Read from file(s) named in arguments (no redirection required)
./slickestWay.pl input.txt
./slickestWay.pl input.txt moreInput.txt
Use a pipe
someOtherScript | ./slickestWay.pl
The BEGIN
block is necessary if you need to initialize some kind of object-oriented interface, such as Text::CSV or some such, which you can add to the shebang with -M
.
-l
and -p
are also your friends.
Upvotes: 18
Reputation: 14472
Do
$userinput = <STDIN>; #read stdin and put it in $userinput
chomp ($userinput); #cut the return / line feed character
if you want to read just one line
Upvotes: 7
Reputation: 17
if(my $file = shift) { # if file is specified, read from that
open(my $fh, '<', $file) or die($!);
while(my $line = <$fh>) {
print $line;
}
}
else { # otherwise, read from STDIN
print while(<>);
}
Upvotes: -2