CODEWITHSUNDEEP
loopspython-3.xif-statement
Lenard
Lenard

Reputation: 821

How Do I return to the top of the loop Python

I need some help on returning to the top of the loop in python I know about the break statement but I do not know if its helpful at all.

Here is my code:

import random

Which_Dice= input("What dice do you want? 4,6 or 12")

if input(Which_Dice)!=("4","6","12"):
    print("Please input the number 4,6 or 12")

elif int(Which_Dice)== 4:
    print(int(Which_Dice), "sided dice thrown", "score",random.randint(0,5))

elif int(Which_Dice)== 6:
    print(int(Which_Dice), "sided dice thrown", "score",random.randint(0,7))

elif int(Which_Dice)==12:
    print(int(Which_Dice), "sided dice thrown", "score",random.randint(0,13))

Upvotes: 0

Views: 621

Answers (2)

SlightlyCrazy
SlightlyCrazy

Reputation: 11

There is no loop in your code but maybe this will help?

def callme():
    Which_Dice= input("What dice do you want? 4,6 or 12")
    .
    .

callme()
callme()

or look into for or while loops.

Upvotes: 1

Maximillian Laumeister
Maximillian Laumeister

Reputation: 20359

If what you want to do is run that part of your program over and over (effectively jumping back up to the top), you can use a while true loop to accomplish that:

import random

while True:

    Which_Dice= input("What dice do you want? 4,6 or 12")

    if input(Which_Dice)!=("4","6","12"):
        print("Please input the number 4,6 or 12")

    elif int(Which_Dice)== 4:
        print(int(Which_Dice), "sided dice thrown", "score",random.randint(0,5))

    elif int(Which_Dice)== 6:
        print(int(Which_Dice), "sided dice thrown", "score",random.randint(0,7))

    elif int(Which_Dice)==12:
        print(int(Which_Dice), "sided dice thrown", "score",random.randint(0,13))

Upvotes: 1

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