CODEWITHSUNDEEP
pythonstring
Joseph Farah
Joseph Farah

Reputation: 2534

Extract Parts of String from in Between Two Characters

If I have a string like this:

string = "12345|67891|23456|123456?"

how would I take out the "12345" and the "67891", etc (the characters between the pipes) and add them to a list all the way until the question mark (I am using the question mark in my code as a terminating character)?

A similar question has been asked here: How do I find the string between two special characters?

but I think mine is different because I need to do it multiple times in the same, one-line string.

Here is what I am hoping to achieve:

[PROGRAM BEGINS]
>>>string = "12345|67891|23456|123456?"
>>>string_list = []
>>>#some code to extract it and add it to a list called string_list
>>>print string_list
["12345","67891","23456","123456"]
[PROGRAM TERMINATES]

Thanks in advance!!

Upvotes: 0

Views: 1137

Answers (6)

rohithvsm
rohithvsm

Reputation: 94

Considering you are using '?' as a terminating char. The safest way to do this would be:

>>> string = "12345|67891|23456|123456?"
>>> string.split('?')[0].split('|')
['12345', '67891', '23456', '123456']

Upvotes: 1

John La Rooy
John La Rooy

Reputation: 304443

If the question mark is always at the end.

>>> string = "12345|67891|23456|123456?"
>>> string.rstrip('?').split('|')
['12345', '67891', '23456', '123456']

regex are relatively slow for performing tasks like this

Upvotes: 2

JOse_M
JOse_M

Reputation: 41

You can use the split function. Str.split("|") and assign the result to an array variable.

Upvotes: 1

Joe T. Boka
Joe T. Boka

Reputation: 6581

You don't need to use the question mark:

>>> string = "12345|67891|23456|123456"
>>> string.split('|')
['12345', '67891', '23456', '123456']
>>>

Upvotes: 1

Iron Fist
Iron Fist

Reputation: 10961

You can do it with re module, this way:

>>>import re
>>>s = "12345|67891|23456|123456?"
>>>string_list = re.findall(r'\d+',s)
>>>string_list
['12345', '67891', '23456', '123456']

Upvotes: 1

Nir Alfasi
Nir Alfasi

Reputation: 53545

You can use regex to split on anything which is not a digit \D:

import re

matches = filter(None, re.split('\D', "12345|67891|23456|123456?"))
print matches # ['12345', '67891', '23456', '123456']

Upvotes: 1

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