CODEWITHSUNDEEP
asp.net-mvc
Ognjen
Ognjen

Reputation: 1195

post data with jQuery and redirect to another action

View: 

<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">

<h2>Index</h2>

<script type="text/javascript">


$(document).ready(function() {

   $(document).ready(function() {

    $("#example").submit(function() {
        var id = $("#id").val();
        var prezime = $("#prezime").val();

        $.post("/jQueryPost/PostingData", { id: id, prezime: prezime }, function(res) {
            if (res.redirect) {
                window.location.href = res.redirect;
                return;
            }

        }, "json");
        return false;
    });
});
</script>

<form id="example" method = "post">

    Id:<input id="id" type="text" />
    Prezime:<input id="prezime" type="text" />

<p>
    <input type="submit" value="Post Data" />
</p>
</form>

</asp:Content>

Controller action:

    [HttpPost]
    public ActionResult PostingData(int id, string prezime)
    {

        //some code

        return Json(new { redirect = Url.Action("Create") });
    }

Tnx, this code solve my problem

Upvotes: 2

Views: 18515

Answers (3)

Walk Walk
Walk Walk

Reputation: 1

controller

public ActionResult DeleteMenuItem(int id)
{
    _menuService.DeleteMenuItemById(id);
    return Json(new { url = Url.Action("Index","Menu") }, JsonRequestBehavior.AllowGet);
}

View

$.getJSON( "/Menu/DeleteMenuItem", { id: parseInt(id)}, function(data) {
    location = data.url;
} );

Upvotes: 0

Guffa
Guffa

Reputation: 700910

The reason that the redirect doesn't work is because you are doing an asynchronous request. The response that contains the code for the redirection is just returned as data to the success method, where you ignore it.

Instead, just post the form that you have in the page:

$('#example').attr('action', '/jQueryPost/PostingData/').submit();

Upvotes: 2

tvanfosson
tvanfosson

Reputation: 532755

Instead of returning a redirect, which the AJAX request can't handle, return the URL as JSON and let the post handler change the location.

$.post("/jQueryPost/PostingData", { id: id, prezime: prezime }, function(data) {
    location = data.url;
});

[HttpPost]
public ActionResult PostingData(int id, string prezime)
{

    //some code

    return Json( new { url = Url.Action( "Create" ) } );
}

Upvotes: 11

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