Reputation: 2366
Having drawn multiple lines using the sin function, I wondered how you would fill in the gap between each of the two lines
float a = 0.0;
float inc = TWO_PI/25.0;
for(int i=0; i<100; i=i+4) {
line(i, 50, i, 50+sin(a)*40.0);
a = a + inc;
}
Upvotes: 3
Views: 261
Reputation: 3084
I would fill it like this:
(It is a pseudocode, You haven't specified the language)
EDIT as @GeorgeProfenza noticed in comment below, you have specified the language
float a = 0.0;
float inc = TWO_PI/100.0; //4x decreased inc
for(int i=0; i<100; i=i+1) { //4x increased count of looping
if(i%4==0){
stroke(0);
}else{
stroke(255,0,0);
}
line(i, 50, i, 50+sin(a)*40.0);
a = a + inc;
}
I would paint lines close together and every fourth will be black
Upvotes: 1
Reputation: 51867
@maskacovnik's solution will work. You can also be a bit cheeky and simply draw a shape:
float a = 0.0;
float inc = TWO_PI/25.0;
beginShape();
for(int i=0; i<=100; i=i+4) {
vertex(i, 50+sin(a)*40.0);
a = a + inc;
}
endShape();
Here's a preview you can run(using js):
function setup() {
createCanvas(100,100);
background(192);
var a = 0.0;
var inc = TWO_PI/25.0;
beginShape();
for(var i=0; i<=100; i=i+4) {
vertex(i, 50+sin(a)*40.0);
a = a + inc;
}
endShape();
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/0.4.6/p5.min.js"></script>
Upvotes: 4