CODEWITHSUNDEEP
carrayscharconstants
Nerd Mom
Nerd Mom

Reputation: 23

How to put variables in const char *array and make size a variable

I have this array which is correct, but I need the values and size to be variable. Is this possible? If so, how?

const char *labels[] = { "Group A", "Group B", "Group C", "Group D", "Group E", "Group F", "Group G", "Group H" };

It has to be a const char * array because it is being used as a stringArray parameter, which won't take anything less complicated.

Any help would be appreciated. Please keep in mind that I am a student developer.

Upvotes: 1

Views: 799

Answers (2)

Giorgi Moniava
Giorgi Moniava

Reputation: 28664

It has to be a const char *array because it is being used as a stringArray parameter, which won't take anything less complicated.

You can pass char* to function expecting const char*.

Given that, maybe you can try something like this:

char**arr = malloc(ARRAY_LEN * sizeof(char*));
for (i=0; i<ARRAY_LEN; i++)
{
     arr[i] = malloc(EACH_STRING_LEN);
     if(arr[i]==NULL) 
        handleError();
     strcpy(arr[i],"test"); // put some string in i-th array
}

and freeing part:

for (i = 0; i < ARRAY_LEN; i++) {
  free(arr[i]);
}
free(arr);

Upvotes: 1

rondoisthebest
rondoisthebest

Reputation: 105

c arrays do not have variable size. If you need this functionality, you have to use a different data structure

What do you mean by "it is being used as a stringArray parameter, which won't take anything less complicated."?

Upvotes: 0

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