CODEWITHSUNDEEP
phpformspostget
Dan Sebastian
Dan Sebastian

Reputation: 549

How to send a part of the form with GET, another with POST?

I'm echoing out a form that uses the method GET to send material via several input type="hidden". Like this:

echo '
<form action="somewhere.php" method="GET" name="whatever" id="whatever">
   <input type="hidden" name="get_method" value=" . '$foo' . ">
   <input type="hidden" name="want_to_send_with_post" value=" . '$my_post' . ">
</form>
';

This works fine, but how do I send one of these input types as POST, since it's the form that determines the method? Is there a way that an individual input type can override the form method? I know that an input button can override the form method (see here), but that's creating a separate entity. I want to send both GET and Post simultaneously.

The reason: I want to send category names with Get and a text message with POST.

Upvotes: 1

Views: 324

Answers (1)

UnstableEagle
UnstableEagle

Reputation: 572

Yeah, you can! Specify the GET data in the URL you're heading to.

(I would edit the GET info with javascript as the user inputs their data)

<input type="text" id="get"> <!--user types get stuff here-->
<form action="somewhere.php?get=something" method="POST" id="form">
    <input type="hidden" name="post" value="<?= $mypost ?>" />
</form>

Use JS to change the GET action 

var form = doc.getId("form")
var get = doc.getId("get").onkeyup = updateLoc;

function updateLoc() {
    form.action = "somewhere.php?get=" + get.value;
}

Then PHP can deal with $_POST["post"] and $_GET["get"] separately.

Upvotes: 1

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