Reputation: 361
I was trying to create a linked list using a for loop but the 'new' in the for loop in the create() method didn't quite allocate a new slot to store new data. As a result, when I tried to print the list, I got an infinite loop. Can somebody tell me what's wrong here?
struct node
{
double value;
node * next_ptr;
node(){}
node(double val, node * p): value(val), next_ptr(p) {}
~node(){}
};
node * create()
{
using namespace std;
node temp = {0, nullptr};
node * result;
for(int i=1; i<5; ++i)
{
result = new node;
result->value = i;
result->next_ptr = &temp;
temp = *result;
}
return result;
};
Upvotes: 1
Views: 8451
Reputation: 1
a simple one to create linked in for loop
#include <iostream>
class LinkedList {
public:
int value;
LinkedList * next;
};
int main()
{
LinkedList *List = nullptr;
LinkedList *head = List;
LinkedList *prev;
for (int i=0; i< 3;i++)
{
LinkedList *temp = new(LinkedList);
temp->value = i;
temp->next = nullptr;
if (head == nullptr)
{
head = temp;
prev = head;
}
else
{
prev->next = temp;
prev = temp;
}
}
}
Upvotes: -1
Reputation: 76240
The reason you are probably getting an infinite loop is because in:
temp = *result;
you are copying the value of *result
into a new object of type node
, which is unrelated to the one you created.
What you want to do is store a pointer instead:
node* temp = nullptr;
node* result;
for(int i=0; i<5; ++i)
{
result = new node;
result->value = i;
result->next_ptr = temp;
temp = result;
}
return result;
A part from the learning value, just stick to std::forward_list
or std::list
, for lists, instead. Or even better just use std::vector
or other containers (depending on the use that you make of the container).
Upvotes: 3