CODEWITHSUNDEEP
mediawikiwikimediawiki-api
Dimentica
Dimentica

Reputation: 805

Wikimedia function to get all my Templates

I need to get all the pages I have created like Templates in my wikimedia webpage. I have to do this with javascript.

Is this possible?

Upvotes: 1

Views: 63

Answers (1)

Ilmari Karonen
Ilmari Karonen

Reputation: 50328

You can do this with a UserContribs API query, like this:

Basically, the parameters you need are:

  • format=json to get results in JSON format, which is probably what you want for JavaScript. (I've used jsonfm in the example link above to get pretty-printed human readable output.)

  • action=query to indicate that this is, indeed, a query rather than, say, an edit or a login attempt.

  • list=usercontribs to indicate that you want a list of a user's contributions (i.e. the stuff you see on the Special:Contributions page).

  • ucuser=your_username to select which user's contributions you want to see. (The example link above shows mine.)

  • ucnamespace=10 to select only contributions to templates. (10 is the namespace number for the built-in Template namespace).

  • ucshow=new to select only contributions that involve creating a new page. (Note that this also includes page moves; I don't see any simple way to filter those out.)

Of course, there are other parameters you may also want to include.

I've also included an empty continue= parameter to indicate that I want to use the new query continuation syntax, and to suppress the warning about it. Obviously, if you actually want to use query continuation, you'll need to implement the client-side part yourself (or use an MW API client that implements it for you). Here's one simplistic way to do that:

function getNewTemplatesForUser( username ) {
    var queryURL = 'https://en.wikipedia.org/w/api.php?format=json&action=query&list=usercontribs&ucnamespace=10&ucshow=new';
    queryURL += '&ucuser=' + encodeURIComponent( username );

    var callback = function( json ) {
        // TODO: actually process the results here

        if ( json.continue ) {
            var continueURL = queryURL;
            for ( var attr in json.continue ) {
                continueURL += '&' + attr + '=' + encodeURIComponent( json.continue[attr] );
            }
            doAjaxRequest( continueURL, callback );
        }
    };
    doAjaxRequest( queryURL + '&continue=', callback );
}

Upvotes: 1

Related Questions